3 years ago

What is the length in units of line segment AB in the resulting figure

Mathematics

1 answer:

nignag [31]3 years ago

8 0

Answer:

5.099

Step-by-step explanation:

You might be interested in

1. In what country did the government debate the merit of teaching students quadratics? 2. What modern technology would not be p

Alexxandr [17]

I would say number 2 but dont take my word for it

6 0

3 years ago

Can you please Simplify 4a+7b+5a-b

vovangra [49]

Answer:

9a+6b

Step-by-step explanation:

4a+7b+5a-b

First figure out the a's 4a + 5a = 9a

Then do b's (Remember, if there is no number by the letter then it is 1)

7b - 1b = 6b

So for this to be simplified the answer is 9a+6b

7 0

3 years ago

What number is represented by these base 10 blocks?

BabaBlast [244]

answer: 1117

the first block is 1000

the second is 100

the third is 10

then the last few count up to 7

5 0

3 years ago

Hamid bought 4.5 pounds of strawberries. The total cost of the strawberries was $8.10. How much did each pound of strawberries c

ankoles [38]

Answer:

$1.80 per pound

Step-by-step explanation:

divide the cost by the number of pounds of strawberries to get your answer

3 0

3 years ago

Read 2 more answers

If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting two queens and two kings.

Bingel [31]

<u>Given</u>:

If you are dealt 4 cards from a shuffled deck of 52 cards.

We need to determine the probability of getting two queens and two kings.

<u>Probability of getting two queens and two kings:</u>

The number of ways of getting two queens is $4C_2$

The number of ways of getting two kings is $4C_2$

Total number of cases is $52C_4$

The probability of getting two queens and two kings is given by

$\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}$

Substituting the values, we get;

$probability=\frac{4C_2 \cdot 4C_2}{52C_4}$

Simplifying, we get;

$probability=\frac{6 (6)}{270725}$

$probability=\frac{36}{270725}$

$probability=0.000133$

Thus, the probability of getting two queens and two kings is 0.000133

7 0

4 years ago