The probability that the sum of Michelle's rolls is 4 is 0.083
∴ P(A)=0.083
Step-by-step explanation:
Given that Michelle is rolling two six-sided dice, numbered one through six.
To find the probability that the sum of her rolls is 4:
∴ n(s)=36
Let P(A) be the probability that the sum of her rolls is 4
Then the possible rolls with sums of 4 can be written as
n(A)=3
The probability that the sum of her rolls is 4 is given by
=0.083
∴ P(A)=0.083
∴ the probability that the sum of Michelle's rolls is 4 is 0.083
-please give brainliest if correct!
The 63 is the err in her explanation here.
1. The weights of 30 students in a class ( in Kg ) are as follows. 42 , 52, 46 ,63, 47 ,40,50,63,52, 57,40,47,55 ,52, 49, 42,56,
enyata [817]
Step-by-step explanation:
I think when you put the numbers orderwise
The range 40 - 50 in which most students lie
