Use pythagorean theorem for all of them
a. 3, 4, 5
3^2+4^2?5^2
9+16?25
25=25
right
b. 5, 6, 7
5^2+6^2=7^2
25+36=49
61>49
acute
c. 64+81=144
145>144
acute
hope this helps!
business and education
since business is wider there is human resource, accounts, finance and among others
Answer:
(a) If r is any rational number and s is any irrational number, then r/s is rational
(b) The statement is false when r is 0
Step-by-step explanation:
Given
rational number
irrational number
irrational number
Solving (a): The negation
To get the negation of a statement, we only need to negate the end result
In other words, the number type of r and s will remain the same, but r/s will be negated.
So, the negation is:
rational number
irrational number
rational number
Solving (b): When r/s is irrational is false
Given that:
irrational number
Set r to 0
So:

-- rational
<em>Hence, the statement is false when r is 0</em>
Answer:
12
Step-by-step explanation:
6x3-6=12
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:(97/17,−64/17)
Equation Form: x=97/17, y=−64/17
plz mark me as brainliest :)