Question

Part C: Find the distance from B to E and from P to E. Show your work. (4 points) image below

Answer 1

The distance from B to E and from P to E are 321.42 and 285.71ft respectively

Similarity theorem of triangles

From the give figure the measure of GR is equal to CP that is;

GR = CP = 350 + 250
GR = 600ft

Using the similarity theorem

BE/BP = GE/GR
BE/250 = 450+BE/600
600BE = 250(450+BE)

600BE = 112500 + 250BE
350BE = 112500
BE = 321.42ft

Similarly

PE/250 = 400/350
350PE = 1000
PE = 285.71ft

Hence the distance from B to E and from P to E are 321.42 and 285.71ft respectively

Learn more on similarity theorem here: brainly.com/question/21247688

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