I need a photo but ill give you some information this will be with exponents.
<em>Write down the problem. Here it is:</em>
<em>2^2(x+3) + 9 - 5 = 32</em>
<em>Resolve the exponent. Remember the order of operations: PEMDAS, which stands for Parentheses, Exponents, Multiplication/Division, and Addition/Subtraction. You can't resolve the parentheses first because x is in the parentheses, so you should start with the exponent, </em><em>2^2.2^2 = 4</em>
<em>4(x+3) + 9 - 5 = 32</em>
<em>Do the multiplication. Just distribute the</em><em> 4 into (x +3)</em><em>. Here's how:</em>
<em>4x + 12 + 9 - 5 = 32</em>
<em>Do the addition and subtraction. Just add or subtract the remaining numbers. Here's how:</em>
<em>4x+21-5 = 32</em>
<em>4x+16 = 32</em>
<em>4x + 16 - 16 = 32 - 16</em>
<em>4x = 16</em>
<em>Isolate the variable. To do this, just divide both sides of the equation by 4 to find x. </em><em>4x/4 = x </em><em>and </em><em>16/4 = 4</em><em>, so </em><em>x = 4.</em>
<em>4x/4 = 16/4</em>
<em>x = 4</em>
<em>Check your work. Just plug </em><em>x = 4</em><em> back into the original equation to make sure that it checks out. Here's how:</em>
<em>2^2(x+3)+ 9 - 5 = 32</em>
<em>2^2(4+3)+ 9 - 5 = 32</em>
<em>2^2(7) + 9 - 5 = 32</em>
<em>4(7) + 9 - 5 = 32</em>
<em>28 + 9 - 5 = 32</em>
<em>37 - 5 = 32</em>
<em>32 = 32</em>
<em><u>Credit to wikiHow.com</u></em>
