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bogdanovich [222]
3 years ago
8

A) 4

Mathematics
1 answer:
Shkiper50 [21]3 years ago
8 0

Answer:

i think c

Step-by-step explanation:

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What is the solution to the given inequality?
xenn [34]

Answer: x ≤3

Step-by-step explanation:

Your answer is correct

7 0
2 years ago
Whats the answer to 3+2h=7
Brut [27]

Greetings! Hope this helps!

Answer

3 + 2h = 7

-3           -3

2h = 4

/2    /2

h = 2

Have a good day!

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A brainliest would help tons! :D

5 0
3 years ago
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Find the length of DB and EC given the length of FB is
aliya0001 [1]

Answer: DB=31.66and EC=49.32

Step-by-step explanation:

4 0
3 years ago
Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has
Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0),  Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8  

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

6 0
3 years ago
How many degrees does the polynomial 6c9 have
spayn [35]

Answer:

None, there are no degrees/exponents

Step-by-step explanation:

Hope this is helpful :)

6 0
3 years ago
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