Answer:
eh im good
Step-by-step explanation:
Answer:

Step-by-step explanation:
A tank contains 240 liters of fluid in which 20 grams of salt is dissolved.
- Volume of the tank = 240 liters
- Initial Amount of Salt in the tank, A(0)=20 grams
Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min
(concentration of salt in inflow)(input rate of fluid)

(concentration of salt in outflow)(output rate of fluid)

Rate of change of the amount of salt in the tank:


We then solve the resulting differential equation by separation of variables.

Taking the integral of both sides

Recall that when t=0, A(t)=20 (our initial condition)

Answer:
Parallel is 3
Perpendicular is - 1/3
Step-by-step explanation:
Good luck!
Answer is <span>7x^2-3x+7
hope this helps</span>
Answer:
11) Irrational number
12) Integer
13) Communitive property of addition
14) Distributive property of addition and multipacation
15) 26
16) 8
17) -41
18) 65
19) -5x-20
Step-by-step explanation:
Hope I helped