Answer:1) bacteria size = b(initial) * e^(r * t)
initial size = 300
final size = 1600.
Substituting the values into the main equation:
1600 = 300 * e^(r * 35 - 20)
solving for 'r'.
1600 = 300 * e^(r * 15)
1600/300 = e^(r * 15)
taking natural log on both sides to eliminate the power
ln(16/3) = ln[e^(r * 15)]
ln(16/3) = r * 15
r = ln(16/3) / 15
= 0.11159843
= 11.16%
To find the initial bacteria size,
Given: t = 20
300 = b * e^(0.1116 * 20)
Solving for b:
300 = b * e^2.232
b = 300/e^2.232
b = 32
Step-by-step explanation:
