A)
s = sweater
j = jeans
Equations:
4s + 2j = 140
2s + 3j = 150
B)
4s + 2j = 140
2s + 3j = 150
Multiply (-2) to the second equation
-2 (2s + 3j = 150)
-4s - 6j = -300
Now you have the equations:
4s + 2j = 140
-4s - 6j = -300
-----------------------------add
-4j = -160
j = 40
4s + 2(40) = 140
4s + 80 = 140
4s = 60
s = 15
The cost for a sweater is $15 and the cost for a jean is $40
We used the elimination method to solve the system of equations.
C)
Each pair of jean, she will buy 3 sweaters so total = 40 + 3(15) = $85
Total cost for 1 pair of jeans and 3 sweaters = $85
If she has $225 the
$225 / $85 = 2.64
2 jeans = 2 x 40 = $80
6 sweaters = 6 x $15 = $90
So She can only buy 2 jeans and 6 sweaters
If her hourly rate stays the same, how many hours would she have<span> to work to earn $217 next week? ... She wants to enlarge the </span>photograph<span> so that its </span>width<span> is 10 in. ... Cross-Multiply: (4)(x)=(6)(10); Simplify: 4x=60; Divide both sides by 4 to find the height of the </span>new photograph<span>: \frac{4x}{4}=\frac{60}{4. Answer: 15 </span>inches<span> .</span>
Answer:
46 and 277
Step-by-step explanation:
Given
f(x) = 
- 8x - 11 ← substitute x = 3, x = - 4 into f(x)
f(3) = 
- 8(3) - 11 = 81 - 24 - 11 = 81 - 35 = 46
f(- 4) = 
- 8(- 4) - 11 = 256 + 32 - 11 = 288 - 11 = 277
What it is asking is 8 times what equals 48. The best way to do this is by doing the opposite operation. 48 divided by 8 equals 6. Then if you put it in the other way you get 8(6)=48 which works out. So the answer is 6.
(7-11) • (5) = -20
A. (5) • 7 + (5) • (-11)
↳ 35 + (-55)
↳ 35 - 55 = -20
B. -(-7+11) • (5)
↳ -4 • 5 = -20
C. (5) • 7 - (5) • 11
↳ 35 - 55 = -20
D. (7+11) • (5)
↳ 18 • 5 = 90
A B & C are correct
