Answer:
Bag 1: 20
Bag 2: 40
Step-by-step explanation:
Let x be the amount taken out of bag 2
Then the amount left in each bag can be written as:
Bag 1: 50-3x
Bag 2: 50-x
Since we know that half of bag 2 is bag 1, that gives us:
50-3x = 1/2(50-x)
-> 50-3x = 25-x/2
Now lets isolate x and solve:
25 = 5x/2
-> 50 = 5x
-> x = 10
So plug x bag in for the original equations:
Bag 1: 50-3x = 50-3(10) = 20
Bag 2: 50-x = 50-10 = 40
Answer:
He owned Cat for 5 years.
Step-by-step explanation:
Given: Owned dog for 9 years.
Dog owned year is one year less than twice as long as he owned a cat.
Lets assume the years that cat has been owned be "x".
Now, finding the number years that Cat hes been owned.
As given, Dog owned year is one year less than twice as long as he owned a cat.
∴ using equation to find the Cat´s owned years.
⇒ 
adding 1 on both side.
⇒ 
dividing both side by 2
⇒
∴x= 
Hence, Cat has been owned for 5 years.
A. 1/10000 because it is a 1/100 chance for each.
b. 1/100 because there are 10,000 options and 100 of them are the same options. Simplify for the answer.
<span>The factors of 60 are 60, 30, 20, 15, 12, 10, 6, 5, 4, 3, 2, 1.The factors of 75 are 75, 25, 15, 5, 3, 1.<span>The common factors of 60 and 75 are 15, 5, 3, 1, intersecting the two sets above.</span><span>In the intersection factors of 60 ∩ factors of 75 the greatest element is 15.</span><span>Therefore, the greatest common factor of 60 and 75 is 15.
</span></span>
Answer:

or

Step-by-step explanation:
Given


![[a,b] = [0,2]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D%20%3D%20%5B0%2C2%5D)
Required
The volume of the solid formed
Rotating about the x-axis.
Using the washer method to calculate the volume, we have:

Integrate


Substitute values for a, b, f(x) and g(x)

Evaluate the exponents

Simplify like terms

Factor out 8

Integrate
![v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0](https://tex.z-dn.net/?f=v%20%3D%208%5Cpi%20%5B%20%5Cfrac%7B2x%5E%7B2%2B1%7D%7D%7B2%2B1%7D%20-%20%5Cfrac%7Bx%5E%7B3%2B1%7D%7D%7B3%2B1%7D%20%5D%7C%5Climit%5E2_0)
![v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0](https://tex.z-dn.net/?f=v%20%3D%208%5Cpi%20%5B%20%5Cfrac%7B2x%5E%7B3%7D%7D%7B3%7D%20-%20%5Cfrac%7Bx%5E%7B4%7D%7D%7B4%7D%20%5D%7C%5Climit%5E2_0)
Substitute 2 and 0 for x, respectively
![v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])](https://tex.z-dn.net/?f=v%20%3D%208%5Cpi%20%28%5B%20%5Cfrac%7B2%2A2%5E%7B3%7D%7D%7B3%7D%20-%20%5Cfrac%7B2%5E%7B4%7D%7D%7B4%7D%20%5D%20-%20%5B%20%5Cfrac%7B2%2A0%5E%7B3%7D%7D%7B3%7D%20-%20%5Cfrac%7B0%5E%7B4%7D%7D%7B4%7D%20%5D%29)
![v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])](https://tex.z-dn.net/?f=v%20%3D%208%5Cpi%20%28%5B%20%5Cfrac%7B2%2A2%5E%7B3%7D%7D%7B3%7D%20-%20%5Cfrac%7B2%5E%7B4%7D%7D%7B4%7D%20%5D%20-%20%5B%200%20-%200%5D%29)
![v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]](https://tex.z-dn.net/?f=v%20%3D%208%5Cpi%20%5B%20%5Cfrac%7B2%2A2%5E%7B3%7D%7D%7B3%7D%20-%20%5Cfrac%7B2%5E%7B4%7D%7D%7B4%7D%20%5D)
![v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]](https://tex.z-dn.net/?f=v%20%3D%208%5Cpi%20%5B%20%5Cfrac%7B16%7D%7B3%7D%20-%20%5Cfrac%7B16%7D%7B4%7D%20%5D)
Take LCM
![v = 8\pi [ \frac{16*4- 16 * 3}{12}]](https://tex.z-dn.net/?f=v%20%3D%208%5Cpi%20%5B%20%5Cfrac%7B16%2A4-%2016%20%2A%203%7D%7B12%7D%5D)
![v = 8\pi [ \frac{64- 48}{12}]](https://tex.z-dn.net/?f=v%20%3D%208%5Cpi%20%5B%20%5Cfrac%7B64-%2048%7D%7B12%7D%5D)

Simplify


or



