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3 years ago

Can someone please help me, everyone is taking my points :(

Mathematics

1 answer:

statuscvo [17]3 years ago

6 0

Answer:Yes that is correct, 3(2t + d) is equal to 6t+3d. This is due to the distributive property of multiplication, or as I like to call it, the DPM. The DPM works for all multiplication and praentheses problems. For example, 7(2t+3d)=14t+21d. You multiply the coefficient of the whole parentheses by each number/variable in the equation. Another example is 5(n+s)=5n+5s.

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What relationship is represented by the graph

frutty [35]

Answer:

the third one

Step-by-step explanation:

area of a circle vs. it's diameter

6 0

2 years ago

Divide 260 in the ratio 1:3

den301095 [7]

The divided will 65 and 195.

1:3 =260
1x+3x =260
Add 1x and 3x
4x=260
Divide the four on both sides
4x/4=260/4
x=65
Now find the one for 3 by multiplying
1x=65
3x=195

5 0

3 years ago

he one‑sample t statistic from a sample of n = 23 observations for the two‑sided test of H 0 : μ = 15 versus H α : μ > 15 has

DedPeter [7]

Answer:

$t = 2.24$

The first step is calculate the degrees of freedom, on this case:

$df=n-1=23-1=22$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(22)}>2.24)=0.01776$

And for this case we can conclude that:

$0.01 < p_v < 0.025$

And we will reject the null hypothesis at $\alpha=0.025$ since $p_v < \alpha$

Step-by-step explanation:

Data given and notation

$\bar X$ represent the mean height for the sample

$s$ represent the sample standard deviation

$n=23$ sample size

$\mu_o =15$ represent the value that we want to test

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 15, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

For this case the statistic is given:

$t = 2.24$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=23-1=22$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(22)}>2.24)=0.01776$

And for this case we can conclude that:

$0.01 < p_v < 0.025$

And we will reject the null hypothesis at $\alpha=0.025$ since $p_v < \alpha$

5 0

3 years ago

Kakakkaiaia919q8q89amamz..z.zjsiaiaiwu: É URGENTE

Alexus [3.1K]

Oh that’s really cool

8 0

3 years ago

Solve for x: 9x-25 = 5x+7

Dennis_Churaev [7]

Answer:

$9x - 25 = 5x + 7 \\ 9x - 5x = 25 + 7 \\ 4x = 32 \\ \frac{4x}{4} = \frac{32}{4} \\ x = 8$

hope this helps....

5 0

3 years ago