All categories

3 years ago

Compare the decimals 18,011.1 and 18,111.01.

1 answer:

4 0

$18,011.1 = 18,011+\frac{1}{10}=18,011+\frac{10}{100} \\ 18,111.01 = 18,111+\frac{1}{100} = 18,011+100+\frac{1}{100}$

$18,111.01 \ \textgreater \ 18,011.1$ because $100+\frac{1}{100}\ \textgreater \ \frac{10}{100} \iff 100 \ \textgreater \ 1 \ \textgreater \ \frac{9}{100}$ .

You might be interested in

Dale runs 10 miles in 75 minutes. At the same rate, how many miles would he run in 69 minutes?

Tems11 [23]

Answer: 9.2 miles

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can Someone help me please I don't understand

Sindrei [870]

Answer:

c i think

Step-by-step explanation:

it's c i think

8 0

3 years ago

2x=3y+1/2 I have to write this in standard form and slope intercept form

Sav [38]

Answer:

Step-by-step explanation:

2x = 3y + 1/2

standard : Ax + By = C

2x = 3y + 1/2....multiply everything by 2 to get rid of the fractions

4x = 6y + 1 ....subtract 6y from both sides

4x - 6y = 1 <==

slope intercept : y = mx + b

2x = 3y + 1/2....subtract 1/2 from both sides

2x - 1/2 = 3y....divide everything by 3

2/3x - 1/6 = y...rearrange

y = 2/3x - 1/6 <===

8 0

3 years ago

Shane is using pieces of square paper to cover a cube shaped gift with sides that are 9 inches long to find out the area of the

nordsb [41]

Answer:

The area of the cube is 486 inches^2

Step-by-step explanation:

In this question, we are tasked with calculating the area of cube with side 9 inch.

Mathematically, the area can be calculated using the formula A = 6s^2

Now, what we need to do is to substitute 9 inches for s

Thus, A = 6 * 9^2

A = 6 * 81

A = 486 inches^2

3 0

3 years ago

the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger

Reil [10]

<h2>Answer:</h2>

$x\geq 3 \ and \ x+1 \geq 4$

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable $x$ which is the smaller number. Accordingly, the lager number will be $x+1$ given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

$\leq \\ which \ means \ less \ than$

So:

1. The sum of 2 consecutive integers can be written as:

$v+(v+1)$

2. Nine times the smaller and 5 times the larger can be written as:

$9v-5(v+1)$

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

$x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\$

$x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4$

The two numbers are:

$x\geq 3 \ and \ x+1 \geq 4$

6 0

3 years ago