Answer:
x = 12, sides = 23
Step-by-step explanation:
Since 
is equilateral, all three sides are equal. Therefore:
![\left[\begin{array}{l}y=2x-1\\y=5x-37\\y=x+11\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bl%7Dy%3D2x-1%5C%5Cy%3D5x-37%5C%5Cy%3Dx%2B11%5Cend%7Barray%7D%5Cright%5D)
Substituting y = x + 11:
![\left[\begin{array}{l}x+11=2x-1\\x+11=5x-37\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bl%7Dx%2B11%3D2x-1%5C%5Cx%2B11%3D5x-37%5Cend%7Barray%7D%5Cright%5D)
Solving for x:
Substituting x = 12:
Thus, <em>x</em> = 12 and the length of each side is 23.
Answer:
x=-1
Step-by-step explanation:
X+0.2=-0.8
x=-1
Answer:
11. B.
12. C.
13. A.
14. D.
Step-by-step explanation:
for 11: we know that angles D and J are congruent from the tick marks, we also know that ∠FKD and ∠LKJ are congruent (vertical angles are congruent) therefore we need the sides between them
for 12: we know that ∠STU and ∠TUG are congruent, we also know that line TU is congruent to TU (reflexive property), therefore we need the angles adjacent to the first angles listed.
for 13: we know that ∠PQR and ∠CQR are congruent, we also know that lines RQ and RQ are congruent (reflexive property), therefore we need the other angles to which line RQ is between.
for 14: we know ∠B is congruent to ∠T and line AB is congruent to line ZY. therefore the angle cannot be connected to lines AB and ZY.
If line segment EF is 28 and F is halfway through the line, then segment EF will be half of 28. So segment EF=14
Answer:
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