Answer:
49x² + 42x + 9
Step-by-step explanation:
Given
(7x + 3)²
= (7x + 3)(7x + 3)
Each term in the second factor is multiplied by each term in the first factor, that is
7x(7x + 3) + 3(7x + 3) ← distribute both parenthesis
= 49x² + 21x + 21x + 9 ← collect like terms
= 49x² + 42x + 9
Well I don't know !
Let's take a look and see:
The idea is that there could be more than one way
for a roll of the dice to land with the same number.
-- If the sum is from 1-4, you get the point.
There are 6 different ways for a roll of the dice to come up 1-4.
-- If the sum is from 5-8, Adam gets the point.
There are 20 different ways for a roll of the dice to come up 5-8.
-- If the sum is 9-12, Lana gets the point.
There are 10 different ways for a roll of the dice to come up 9-12.
-- The game is not fair to all three of you.
-- Lana has a distinct advantage over you.
-- Adam has a big advantage over Lana.
-- Adam has an even bigger advantage over you.
-- You are at a big disadvantage. (Notice that one of your
numbers ... 1 ... can never come up unless one of the dice
falls off of the table.)
_______________________________
Here's how to figure it:
Ways to roll a 2:
1 ... 1
Ways to roll a 3:
1 ... 2
2 ... 1
Ways to roll a 4:
1 ... 3
2 ... 2
3 ... 1
Ways to roll a 5:
1 ... 4
2 ... 3
3 ... 2
4 ... 1
Ways to roll a 6:
1 ... 5
2 ... 4
3 ... 3
4 ... 2
5 ... 1
Ways to roll a 7:
1 ... 6
2 ... 5
3 ... 4
4 ... 3
5 ... 2
6 ... 1
Ways to roll an 8:
2 ... 6
3 ... 5
4 ... 4
5 ... 3
6 ... 2
Ways to roll a 9:
3 ... 6
4 ... 5
5 ... 4
6 ... 3
Ways to roll a 10:
4 ... 6
5 ... 5
6 ... 4
Ways to roll 11:
5 ... 6
6 ... 5
Ways to roll 12:
6 ... 6
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula 
to find the distance from point 
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: 
.
Answer:
.8>63%
Step-by-step explanation:
