Answer:
#1). 6 , 18 , 54
#2). 5/3 , 14 / 9 , 41/27
#3). 1.5 , 2.5 , 2.5
Step-by-step explanation:
#1).
g(x) = 3x
g(2) = 3 . 2 = 6
g²(2) = 3 . 3 . 2 = 18
g³(2) = 3 . 3 . 3 . 2 = 54
#2).
g(x) = 1/3 x + 1
g(2) = 2/3 + 1 = 5/3
g²(2) = g(5/3) = 5/9 + 1 = 14/9
g³(2) = g(14/9) = 14/27 + 1 = 41/27
#3).
g(x) = -1 ║x - 2 ║ + 3
g(0.5) = -1 (1.5) + 3 = 1.5
g²(0.5) = g(1.5) = -1(0.5) + 3 = 2.5
g³(0.5) = g(2.5) = -1(0.5) + 3 = 2.5
Exactly one activity:
246None of the activities :
1At least one activity:
74Snowboarding and Ice skating but not skiing:
5Snowboarding or ice skating but not skiing:
132.
Only skiing :
119.
The diagram is in the attachment.
Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;


Divide by m to isolate
.


To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)