<h3>Answers:</h3>
- A(10) = 10
- A(0) = 0
- A(-3) = 3
- A(3.14159) = 3.14159
- A(x) = 7 leads to either x = 7 or x = -7
- A(x) = -5 has no solutions
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Explanations:
The piecewise function has two identities based on what the x input is.
If x = 0 or larger, then A(x) = x based on the top row.
Or, if x < 0, then A(x) = -x based on the second row.
So for an input like x = 10, we have A(10) = 10. The input is identical to the output. The same goes for x = 0 and x = 3.14159
Each output tells us how far away the input is from zero on the number line.
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For a negative input, we'll use the second row
A(x) = -x
A(x) = -(x)
A(-3) = -(-3)
A(-3) = 3
Showing that the number -3 is exactly 3 units away from zero on the number line. In other words, |-3| = 3.
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To solve A(x) = 7, we have to think what input(s) will lead to an output of 7.
What two numbers are 7 units away from zero on the number line? That would be -7 and 7.
If you plugged x = 7 into the piecewise function, you'll use the top row to get A(7) = 7. The bottom row will have A(-7) = 7.
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There are no solutions to A(x) = -5 because the result of an absolute value is never negative. Negative distances do not make sense, so that's why absolute value is defined this way.
If you tried x = 5 then A(5) = 5
Trying x = -5 leads to A(-5) = 5
There's no way to get a negative output.
