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3 years ago

(Sin(2x))/((e^(x)^(3))+√(x^2+4))

Mathematics

1 answer:

murzikaleks [220]3 years ago

3 0

I am sorry I cannot solve this problem.

However, I have a tip: if you are gonna give

problems as hard as these, you might wanna offer more than just 5 points. Or you can just waste your points and get a zillion non-helpful answers like this one.

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The function y= x2 - 10x+ 31 has a value of

Margarita [4]

Answer:

y = 6 at x = 5

Step-by-step explanation:

It is assumed the question is about finding the minimum value as the given function has no maximum value, it is + ∞ as the coefficient of x² is positive

The minimum/maximum value of a quadratic function is the vertex, which is at:

x = -b/2a

For the given function y = x² -10x + 31, the vertex is:

x = - (-10)/2*1 = 10/2 = 5

The value of y at this point is:

y = 5² - 10*5 + 31 = 25 - 50 + 31 = 6

The point is

(5, 6)

5 0

3 years ago

Mr. Peters is planning to buy a new house. His friends suggest that he find out the actual dimensions of the property. What shou

slamgirl [31]

I would say surface area or volume

4 0

3 years ago

Read 2 more answers

Suppose each license plate in a certain state has three letters followed by three digits. The letters and and the digits , , and

exis [7]

Answer:

17576000 different possible license plates

Step-by-step explanation:

Note that in the question, repetition is allowed for both the letters and digits.

For the first letter, there are 26 choices to make. For the each of the letters, there are 26 choices for the second letter, and for each of the letters, there are another 26 choices for the third letter.

Therefore, this gives us 26x26x26 = 17576 possible pairs of letters.

For the three numbers, we have ten possibilities for the first digit, ten possibilities for the second digit, and ten possibilities for the third digit.

Therefore, this gives us 10x10x10 =1000 possible numbers.

The combined possibility of the license plates in both three letters and three numbers is 17576 x 1000 = 17576000 different possible license plates.

7 0

3 years ago

Mae has a number cube with 6 sides that are numbered 1 through 6. What is the probability that Mae will roll an odd number?

Stels [109]

Answer:

C) $P(E) = \frac{3}{6}$

The probability that Mae will roll an odd number

$P(E) = \frac{3}{6}$

Step-by-step explanation:

Step(i):-

Given that Mae has a number cube with 6 sides that are numbered 1 through 6.

n(S) = { 1,2,3,4,5,6,} = 6

Let 'E ' be the event of odd numbers

Mae will roll an odd number

n(E) = {1, 3, 5} = 3

Step(ii):-

The probability that Mae will roll an odd number

$P(E) = \frac{n(E)}{n(S)} = \frac{3}{6}$

$P(E) = \frac{3}{6}$

4 0

3 years ago

You receive an $18 commission on a

Alenkasestr [34]

Answer:

Step-by-step explanation:

300 ÷ 3 = 100

18 ÷ 3 = 6

4 0

3 years ago