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3 years ago

PLEASE HELP,, MARKING BRAINLIEST!! What is the scale factor?

Mathematics

1 answer:

Rasek [7]3 years ago

8 0

Answer:

1.3

Step-by-step explanation:

If you were to align the triangles, for example, E,B to J,R they would be proportional. So the scale factor is 1.3

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Write an expression to represent the pattern 19, 27, 35, 43

Mama L [17]

Answer

1) The expression to represent the pattern is 11 + 8n

2) The expression to represent the pattern is 80 - 9n

Step-by-step explanation:

1) Lets study the pattern;

- 19 , 27 , 35 , 43 , ..................

27 - 19 = 8

35 - 27 = 8

43 - 35 = 8

The difference is constant between each two consecutive terms

It is an arithmetic sequence

Lets take about the arithmetic sequence

If the first term is a and the constant difference is d

a1 = a , a2 = a + d , a3 = a + 2d , a4 = a+ 3d , ........

an = a + (n - 1)d, where n the position of the term in the sequence

Now we will use this rule to find the expression of our pattern

a = 19 , d = 8

an = 19 + (n - 1)(8) ⇒ an = 19 + 8n - 8 ⇒ an = 11 + 8n

Lets check it;

a3 = 11 + 8(3) = 11 + 24 = 35 ⇒ true

The expression to represent the pattern is 11 + 8n

Step 2) Lets study the pattern;

- 71 , 62 , 53 , 44 , ...

62 - 71 = -9

53 - 62 = -9

44 - 53 = -9

The difference is constant between each two consecutive terms

It is an arithmetic sequence

We will use the same rule above to find the expression of the pattern

a = 71 , d = -9

an = 71 + (n - 1)(-9) ⇒ an = 71 + -9n + 9 ⇒ an = 80 - 9n

Lets check it;

a4 = 80 - 9(4) = 80 - 36 = 44 ⇒ true

The expression to represent the pattern is 80 - 9n

7 0

3 years ago

Can someone help me with 23?

maxonik [38]

2.5 pounds of apples * $1.20 = $3

He spent total $4.50

So he had to have spent 1.50 on oranges.

So $1.50=$1.20 x where x will be the pound of oranges bought.

1.50/1.20 = 1.25 or 1 1/4 pounds of oranges.

3 0

3 years ago

The radius of a circle is 2.9 in. Find the circumference to the nearest tenth (help please)

nika2105 [10]

Answer:4.18

Step-by-step explanation:

2.9+2/9

4 0

3 years ago

Read 2 more answers

Julian fully simplifies this polynomial and then writes it in standard form. 4x2y2 – 2y4 – 8xy3 + 9x3y + 6y4 – 2xy3 – 3x4 + x2y2

ollegr [7]

Given that the last term is -3x^4, the polynomila is ordered in descending order of the exponent of x. Then, the first term is that where y is with the highest exponent, that is y^4

Simplify the terms with y^4: -2y^4 + 6y^4 = 4y^4

Then the first term is 4y^4

6 0

3 years ago

Read 2 more answers

Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete

Katyanochek1 [597]

Answer:

b/a
16a²b²
n¹⁰/(16m⁶)
y⁸/x¹⁰
m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

3 0

3 years ago