Answer:
The height of near by tree will be 90 feet.
Step-by-step explanation:
Considering the water triangle as shown in figure a.
As the old faithful shoots water 60 feet into the air that casts a shadow of 42 feet.
Considering the tree triangle as shown in figure a. The tree triangle has a shadow 63 feet long.
Let x be the height of near by tree that cost a shadow 63 feet long.
Assuming that the triangles are similar
So,
the ratios of similar triangles will be related as:




feet
Therefore, the height of near by tree will be 90 feet.
Keywords: ratio, similar triangle
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The volume is V=399.48 m to the power of three
Answer: The answer is A
Step-by-step explanation: You use normalcdf to find the area under a curve. The lower bound (in this case 7) goes first followed by the upper bound, mean, and standard deviation.
Answer:
Using the Sine Rule , which states that

In Δ ABC
∠A +∠B+∠C=180°→→Angle Sum Property of Triangle
72°+85°+∠C=180°
∠C=180° - 157°
∠C= 23°
All the angles are in degrees.

Using the table of Sine, Calculating Sine Values
Sin 72°= 0.9510
Sin 85°=0.996
Sin 23°=0.390

Among the five Options,
Option E: a= 15.09 and b=15.81 is approximately true.
We can create two equations here:
(1) Volume = area of square * height of box
85.75 = s^2 h
(2) Cost = 3 * area of square + 1.5 * area of side box
C = 3 s^2 + 1.5 s h
From (1), we get:
h = 85.75 / s^2
Combining this with (2):
C = 3 s^2 + 1.5 s (85.75 / s^2)
C = 3 s^2 + 128.625 s-
Taking the 1st derivative and equating dC/ds =
0:
dC/ds = 6s – 128.625 / s^2 = 0
Multiply all by s^2:
6s^3 – 128.625 = 0
6s^3 = 128.625
s = 2.78 cm
So h is:
h = 85.75 / s^2 = 85.75 / (2.78)^2
h = 11.10 cm
So the dimensions are 2.78 cm x 2.78 cm x 11.10 cm
The total cost now is:
C = 3 (2.78)^2 + 1.5 (2.78) (11.10)
C = $69.47