Find the area please

Please help me with this question<br> Picture included

svetlana [45]

<span>1/4+3/4+3 3/4+1 1/2+5 1/2, which is 11 3/4 ounces.</span>

7 0

3 years ago

PLZ HELP if u know the answer for sure

krok68 [10]

The answer is b (-2 5/6)

6 0

3 years ago

Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.

DENIUS [597]

Answer:

The probability that a randomly chosen plate contains the number 2222 is 0.000028 approximately.

The probability that a randomly chosen plate contains the sub-string HI is 0.002548 approximately.

Step-by-step explanation:

Consider the provided information.

Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.

Part (A)

Let A is the ways in which plates consist of three letters followed by three digits and B is the ways in which two letters followed by four digits.

Here repetition is allow. The number of alphabets are 26 and the number of distinct digits are 10.

The numbers of ways in which three letters followed by three digits can be chosen is: $26\times 26\times 26 \times 10 \times 10 \times10$

$26^3\times 10^3=17576000$

The numbers of ways in which two letters followed by four digits can be chosen is: $26\times 26\times 10 \times 10 \times 10 \times10$

$26^2\times 10^4=6760000$

Hence, the total number of ways are 17576000 + 6760000 = 24336000

Randomly chosen plate contains the number 2222 that means the first two letter can be any alphabets but the rest of the digit should be 2222.

Thus, the total number of ways that a randomly chosen plate contains the number 2222 number are: $26^2=676$

The probability that a randomly chosen plate contains the number 2222 is:

$\frac{676}{24336000} \approx 0.000028$

Part (B)

The number of ways in which chosen plate contains the sub-string HI:

If three letters followed by three digits plate contains the sub-string HI, then the number of possible ways are:

$26\times 1\times10^3+1\times 26\times10^3$

If two letters followed by four digits plate contains the sub-string HI, then the number of possible ways are:

$1\times 10^4$

Thus, the total number of ways that a randomly chosen plate contains the sub-string HI are:

$1\times 10^4+26\times 1\times10^3+1\times 26\times10^3$

$62000$

From part (A) we know that the total number of ways to chose a number plate is 24336000.

The probability that a randomly chosen plate contains the sub-string HI is:

$\frac{62000}{24336000} \approx 0.002548$

7 0

3 years ago

(Will award Fast Brainliest & Many Points!)

Softa [21]

Answer:

A] The slope of f(x) is greater than the slope of g(x).

Step-by-step explanation:

First, you need to calculate the slope of f(x) and g(x) using the slope formula

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are points of the functions.

To calculate the slope of f(x) you can choose two points from the graph, in this case (0, -1) and (3, 1). Remember you can choose the points you want as long they are on the graph.

m = 1 - (-1) / 3 - 0

m = 1 + 1 / 3

m = 2 / 3

m = 0.66...

To calculate the slope of g(x) you can choose two points from the table, in this case (0, 2) and (5, 4).

m = 4 - 2 / 5 - 0

m = 2 / 5

m = 0.4

So the slope of f(x) is greater than the slope of g(x).

3 0

3 years ago

If 1/10m = 1/11m + 1/1100, what is the value of m?

valentinak56 [21]

$\frac{1}{10m} = \frac{1}{11m} + \frac{1}{1100} 
$
$\frac{1}{10m} = \frac{1*1100 + 1*11m}{11m*1100}$
$\frac{1}{10m} = \frac{1100 + 11m}{12100m}$
$1*12100m = 10m(1100 + 11m)$
$12100m = 11000m + 110 m^{2}$
$12100m-11000m = 110 m^{2}$
$1100m = 110 m^{2}$
m=10

3 0

3 years ago

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Find the area please​

Find the area please