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alexandr1967 [171]
3 years ago
9

What is the missing part​

Mathematics
1 answer:
GrogVix [38]3 years ago
7 0
Do 24 times 25 and then divide that in half
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Simplify (8x^3-5x-1)-(7x^2+6x-10)
irakobra [83]

Answer:

8x^3-7x^2-11x+9

Step-by-step explanation:

(8x^3-5x-1)-(7x^2+6x-10)

remove unnesasary ( )

8x^3-5x-1 -(7x^2+6x-10)

the distribute

8x^3-5x-1 -7x^2-6x+10

combine like terms

8x^3-11x+9-7x^2

use the communative property to reorder the equation

8x^3-7x^2-11x+9

4 0
3 years ago
Heleeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeep
murzikaleks [220]

Answer:

3.625 is ans

Step-by-step explanation:

4.5+0.25_+1.125=3.625

5 0
3 years ago
Read 2 more answers
Jaime en un joven que vive en puyo con su padre. A jaime le gusta cosechar chonta con su padre los sabados en la mañana jaime ha
xenn [34]

Answer:

\large \boxed{\text{23 s}}

Step-by-step explanation:

Jaime is at point A and wants to get across the river to Point B.

They must head upstream towards Point C.

1. Calculate the net speed across the river.

∆ABC is a right triangle, so

\begin{array}{rcl}AB^{2} + BC^{2} & = & AC^{2} \\AB^{2} +10^{2} & = & 12^{2} \\AB^{2}+100& = & 144 \\AB^{2}& = & 44\\AB & = & \sqrt{44}\\& = & 2\sqrt{11}\\& \approx &\textbf{6.633 m/s}\\\end{array}

2. Calculate the time to cross the river

\text{Time} = \text{150 m} \times \dfrac{\text{1 s}}{\text{6.633 m}} \approx \textbf{23 s}\\\\\text{It will take $\large \boxed{\textbf{23 s}}$ to cross the river.}

7 0
3 years ago
Write an equation that represents the volume V as a function of the height h
erma4kov [3.2K]

Answer:

h=V/b

Step-by-step explanation:

5 0
3 years ago
I'll mark brainliest just tell me how to.
IRINA_888 [86]

Answer:

a = 12

b = 2

c = 11

Step-by-step explanation:

\frac{( {x}^{5}y  {z}^{4} )^{3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{5 \times 3}y^{3}   {z}^{4 \times 3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{15}y^{3}   {z}^{12} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\  {x}^{15 - 3}  {y}^{3 - 1}  {z}^{12 - 1} =  {x}^{a}  {y}^{b}  {z}^{c} \\  \\  {x}^{12}  {y}^{2}  {z}^{11} =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ equating \: like \: terms \: from \: both \: sides \\  \\  {x}^{12}  =  {x}^{a}  \:  \implies \: a = \boxed{ 12}\\  \\  {y}^{2}  =  {y}^{b}  \:  \implies \: b = \boxed{ 2} \\  \\  {z}^{11}  =  {z}^{c}  \:  \implies \: c = \boxed{ 11}

3 0
3 years ago
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