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lubasha [3.4K]
2 years ago
5

Malik grills a steak 45 minutes longer than he grills a serving of fish. The fish takes twice as long as the asparagus to grill.

Malik grills halved tomatoes for 3 minutes, which is 3 minute longer than he grills the asparagus. 3 33 This question has 3 parts. Be sure to complete all parts. A Directions: Type your response in the box. Write an expression that represents the amount of time Malik grills the steak if the asparagus grills for x minutes.​

Mathematics
1 answer:
stellarik [79]2 years ago
3 0

Vasellasar26,

Penso che tu parli italiano, quindi ecco la risposta alla domanda in italiano. Malik griglia una bistecca 45 minuti in più rispetto a u.na porzione di pesce. Il pesce impiega il doppio del tempo per grigliare gli asparagi. Malik griglia i pomodori tagliati a metà per 3 minuti, che è 3 minuti in più rispetto a quando griglia gli asparagi. 3 33 Questa domanda è composta da 3 parti. Assicurati di completare tutte le parti. A Indicazioni: digita la tua risposta nella casella. Scrivi un'espressione che rappresenti il ​​tempo durante il quale Malik griglia la bistecca se gli asparagi grigliano x minuti.

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The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

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