Answer:
The 95% confidence interval for mean compressive strength is:

Step-by-step explanation:
We have a sample of n=12 specimens, with sample mean=3259.9 and sample standard deviation = 35.57.
We know the population is normally distributed.
For a 95% confidence interval and df=n-1=11, the t-statistic is t=2.201.
Then, the CI can be expressed as:

So all you do is you divide 2 1/2 by .25 and you get 10 then you know one fourth or 25% of that package is 10 berries so the rest or 30% left over is 30 berries.
2+4+8=14
2x4x8=64
2x4=8
8x8=64
Answer:
y=-4x+50, y=2x-10 ( i think)
Step-by-step explanation: