I believe that the answer to the question provided above is that <span>the maximum total area that 450 cm of string can enclose if it is used to form the perimeters of two is area = 12 656.25 sqr cm. 450/4 = x . x^2 = area</span>
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Answer:
the mean is 3
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Step-by-step explanation:
Answer:
Step-by-step explanation:
1. Supplementary
2. complementary
3. neither
4. These two are vertically opposite so neither.
5. Supplementary
6. They add to 90 so they are complementary
7. They add to 180 so they are supplementary.
8. These 2 are equal and vertically opposite. They are neither for this exercise.
9. Complementary: they add to 90.
Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says "
times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:
Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:
2. Charlene's rhombus:
Dividing the area calculated, you get:
Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Answer:
x-3 and y=2
Step-by-step explanation:
