What I’d the first step? How do I find angle A?

Mathematics

2 answers:

BartSMP [9]2 years ago

7 0

Answer:

charity activity trivia señora Sonia de warrior Gloria Delaware 853

anzhelika [568]2 years ago

3 0

Answer: charity activity trivia señora Sonia de warrior Gloria Delaware 853

Step-by-step explanation:

You might be interested in

What is the interquartile range of the data set? Enter the answer in the box. Key: 1|5 means 15

Aneli [31]

First of all we have to arrange the data in ascending order as shown below:

28, 40, 43, 43, 45, 50, 50

Total number of values = 7

Since the number of values is odd, the median will be the middle value i.e. 4th value which is 43. Median divides the data in two halves:

1st Half = 28, 40, 43
2nd Half = 45, 50, 50

Q1 or the First Quartile is the middle value of the lower or 1st half which is 40.
Q3 or the Third Quartile is the middle value of the upper or second half, which is 50.

IQR or the Inter Quartile Range is the difference of Q3 and Q1.

So, IQR= Q3 – Q1 = 50 – 40 = 10

Thus, IQR for the given data is 10

4 0

3 years ago

Read 2 more answers

Solve for x 6x²+2x-12

dem82 [27]

Answer:

Step-by-step explanation:

Solving for x means you have to factor. First factor out the GCF of 2 to get:

$2(3x^2+x-6)$ and now we'll factor using the regular old method of ac and then factoring by grouping. In our polynomial, a = 3, b = 1, c = -6. Therefore, a times c is 3 * -6 which is -18. We need some combinations of the factors of 18 that will add to give us 1, the b term in the middle. The factors of 18 are:

1, 18

2, 9

3, 6 and that's it. Hm...it seems that won't work, so let's throw this into the quadratic formula, going back to the original and a = 6, b = 2 and c = -12:

$x=\frac{-2+/-\sqrt{2^2-4(6)(-12)} }{2(6)}$ and

$x=\frac{-2+/-\sqrt{4+288} }{12}$ and

$x=\frac{-2+/-\sqrt{292} }{12}$ and

$x=\frac{-2+/-\sqrt{4*73} }{12}$ and

$x=\frac{-2+/-2\sqrt{73} }{12}$ which finally simplifies to

$x=\frac{-1+/-\sqrt{73} }{6}$ No wonder that didn't factor using the traditional method of factoring! We could have found that out by finding first the value of the discriminant, but oh well!