Answer:
Step-by-step explanation:
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second. What are the two numbers?
Two consecutive year positive integers are represented by
x and x + 1
First integer = x
Second integer = y
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second.
This is represented mathematically as:
x² = 364 + 5(x + 1)
x² = 364 + 5x + 5
x² -5x -5 - 364
x² - 5x - 369
Answer: 12.48
Step-by-step explanation:
38x38+bxb=40x40
1444+b=1600
1600-1444=156
=12.48
Not sure sorry I’m not good at math need help with something else..
What you do is you find the common denominator between the two fractions given. the easiest is to just multiply them
6*8=48
and then multiply each numerator by the number it's denominator is multiplied by
1*8=8 and 5*6=30
and now you have your new fractions, add them together
8/48+30/48=38/48
this leaves 10/48 as the people who were wearing shorts, just simplify this and it's done
10/2 =5/24
48/2
Answer:
345 times 0.03 = 10.35 but we cant have 0.35 of a person so it is 10 people
Step-by-step explanation: