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Alexus [3.1K]
3 years ago
8

Which point is best represented by the ordered pair (2, -5.5)?

Mathematics
1 answer:
Kryger [21]3 years ago
3 0

Answer:

the answer is b

Step-by-step explanation:

because the point is located at the number given the answer is b

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A shop makes 3250£ in march in april it makes 3542.50£ what if the percentage increase
babunello [35]

Answer:

1.09

Step-by-step explanation:

3250 x 1.09 =  £3542.50

7 0
4 years ago
Is 0.032 a terminating decimal
svp [43]
I don’t think it is, sorry I’m not 100% sure, good luck though
3 0
4 years ago
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
2 years ago
Question 2 (Multiple Choice Worth 5 points)
steposvetlana [31]
Number of remaining rose cards = 6
number of remaining cards = 8
P(rose card) = 6/8

P(blue marble) = 18/50
P(tail) = 30/50
P(blue marble and tail) = 18/50 x 30/50 = 540/2500
6 0
4 years ago
What is the factorization of 3x^2 – 8x + 5?
hodyreva [135]
3x^2 - 8x + 5
3x^2 - 3x - 5x + 5
3x(x - 1) - 5(x - 1)
(x - 1)(3x - 5)

The answer is: (x - 1)(3x - 5).
5 0
3 years ago
Read 2 more answers
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