Answer:
x=7 and m<LMN = 120
Step-by-step explanation:
if MO bisects LMN then 13x - 31 must be equal to x + 53
13x - x = 53 + 31
12x = 84
x = 7
and
13x - 31 + x + 53 = m<LMN
14x + 22 = m<LMN
since x is 7
14×7 + 22 = 120
9514 1404 393
Answer:
119 4/7
Step-by-step explanation:
The perimeter is the sum of side lengths.
10 1/7 + 12 2/7 + 15 3/14 + 24 1/14 + 12 2/7 + 10 1/7 + 35 3/7
= (10 + 12 + 15 + 24 + 12 + 10 + 35) + (1 + 2 + 2 + 1 + 3)/7 + (3 + 1)/14
= 118 + 9/7 + 4/14
= 118 + 1 2/7 + 2/7
= 119 4/7 . . . . perimeter of the figure
<span>Each team in the softball league plays each of the other teams exactly once. For every game, there is 2 team playing. The order is not important because A vs B is same as B vs A
So you just need to makes a combination of 2 that have a result of 21. If there is t number of teams, the number of matches would be:
tC2 = t!/2!(t-2)! = 21
</span>t! / (t-2)! = 21 *2
(t)(t-1)= 42
t^2 -t -42=0
(t-7)(t+6)
t=7 ; t=-6
Excluding the minus result, you got 7 teams.
Answer:
Step-by-step explanation:
The type I error occurs when the researchers rejects the null hypothesis when it is actually true.
The type II error occurs when the researchers fails to reject the null hypothesis when it is not true.
Null hypothesis: The proportion of people who write with their left hand is equal to 0.23: p =0.23
Type I error would be: Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually different from 0.29
Since 0.29 is assumed to be the alternative claim.
Type II error would be: Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29
Still with the assumption that 0.29 is the alternative claim.
