Answer:
The poster is 11 inches wide and 19 inches in height.
Step-by-step explanation:
We take the given equation: (x^2+2x-15) and we add in 14 as our x variable:
((14)^2+2(14)-15) the answer we get from that is 209. The area of the poster is 209 square inches. Then we find the width by taking (x-3) in this case x is 14 so the width of the poster is 11. In order to find the height we divide the height by the width and we get 19.
Therefore:
Height= 19 Inches
Width= 11 Inches
Total Area= 209 Square Inches
Answer:
that would 6a+4
Step-by-step explanation:
8a - 2a , 8 - 4
Answer:
A
Step-by-step explanation:
There answer
The area of the square whose sides is s inches long will be given by:
Area=length×width
Length=s inches
width=s inches
thus:
the area of the squares will be:
Area=s×s=s² sq. inches
Thus the correct answer is:
area=s² sq. in
Step-by-step explanation:
(1) Factor the GCF out of the trinomial on the left side of the equation. (2 points: 1 for the GCF, 1 for the trinomial) 2x²+6x-20=0
2x²+6x-20
2(x²+3x-10)
the factors are 2 and (x²+3x-10)
(2) Factor the polynomial completely. (4 points: 2 point for each factor)
2(x²+3x-10)
2(x²-2x+5x-10)
2(x(x-2) + 5(x-2)) group like terms
2(x+5)(x-2)
(3) If a product is equal to zero, we know at least one of the factors must be zero. And the constant factor cannot be zero. So set each binomial factor equal to 0 and solve for x, the width of your project. (2 points: 1 point for each factor)
constant = 2 cannot be zero
the other factors are (x+5) and (x-2)
(x+5)=0 => x= -5
or
(x-2)=0 => x=2
(4) What are the dimensions of your project? Remember that the width of your project is represented by x. (2 points: 1 point for each dimension)
thank you so much, sorry if it's a little confusing!!
(it is indeed confusing, because physical dimensions cannot be negative)
The dimensions of the project (assumed a rectangle) are +2 and -5
