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TEA [102]
4 years ago
14

Angles that share a vertex, but not a side are called

Mathematics
1 answer:
djyliett [7]4 years ago
7 0
Adjacent angles-
  2 angles that share a common vertex, a common side and no common interior points.

The answer is ADJACENT ANGLE

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ou invested 7000 between two accounts paying 4% and 9% annual​ interest, respectively. If the total interest earned for the year
lana [24]

9514 1404 393

Answer:

  • $3000 at 9%
  • $4000 at 4%

Step-by-step explanation:

Let x represent the amount invested at 9%. Then 7000-x was invested at 4% and the interest earned was ...

  9%·x +4%(7000-x) = 430

  5%·x +280 = 430 . . . . . . . . . simplify

  0.05x = 150 . . . . . . . . . . . subtract 280

  x = 3000 . . . . . . . . . . divide by 0.05

$3000 was invested at 9%; $4000 was invested at 4%.

7 0
3 years ago
I need to know the answer to 2 1/3 x 4/5
Sever21 [200]

Answer:

Simplify the expression.

Exact Form:

28/15

Decimal Form:

1.8¯6

Mixed Number Form:

1 13/15

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The volume
Sedaia [141]
\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
&&  y={{ k }}x
\end{array}\\ \quad \\


and also

\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
&&y=\cfrac{{{  k}}}{x}
\end{array}


now, we know that V varies directly to T and inversely to P simultaneously
thus\bf V=T\cdot \cfrac{k}{P}

so     \bf V=T\cdot \cfrac{k}{P}\qquad 
\begin{cases}
V=42\\
T=84\\
P=8
\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k
\\\\\\
V=\cfrac{4T}{P}\qquad now\quad 
\begin{cases}
V=74\\
P=10
\end{cases}\implies 74=\cfrac{4T}{10}\implies 185=T
7 0
3 years ago
Someone please help!!! Can’t find this one anywhere!!! please and thank you!!!!!!!
Tema [17]

\dfrac{ 2+ 2i}{5+4i}\\\\\\=\dfrac{(2+2i)(5-4i)}{(5+4i)(5-4i)}\\\\\\=\dfrac{10-8i + 10i -8i^2}{5^2 -(4i)^2}\\\\\\=\dfrac{10+2i +8}{25+16}~~~~;[i^2 =-1]\\\\\\=\dfrac{18+2i}{41}\\\\\\=\dfrac{18}{41} + \dfrac{2}{41}i

4 0
2 years ago
What is the answer to this problem<br> 2(6y-2)-3y=2
tester [92]

Answer:

y=9/6 (3/2 simplified)

Step-by-step explanation:

2(6y-2)-3y=2

12y-4-3y=2

ad 4 both side

12y-3y=6

9y=6

9/6

5 0
3 years ago
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