Solve for r in the first equation:
3(r+300) = 6
Use the distributive property:
3r + 900 = 6
Subtract 900 from both sides:
3r = -894
Divide both sides by 3:
r = -894 / 3
r = -298
Now you have r, replace r in the second equation and solve:
r +300 -2 =
-298 + 300 - 2 = 0
The answer is 0.
Answer:
No
Step-by-step explanation:
Let's find the slope of both lines and then compare these slopes:
From (-4,3) to (-5,4) entails a decrease of -1 in x and an increase of 1 in y. Thus, the slope is m = rise / run = 1/(-1) = -1.
From (0,1) to (5,0) entails an increase of 5 in x and a decrease of 1 in y. The slope here is m = rise / run = -1/5.
For these lines to be parallel, their slopes must be the same. That is not the case here, so NO, the lines are not parallel.
Answer:
(1, -1)
Step-by-step explanation:
we isolate y in the first equation
2x+y=1
-2x. -2x
y=1-2x
and now we fill y into second equation
4x-2(1-2x)=6
4x-2+4x=6
8x-2=6
+2 +2
8x=8
/8 /8
x=1
and now to find y we insert x
2(1)+y=1
2+y=1
-2. -2
y= -1
hopes this helps
Answer:
RK= 13 SK= 12
Step-by-step explanation
First, we find the missing length of RK using the given information: 65-52=13
Then we divide 65 by 13 to get a scale factor: 65/13=5
(To check, we multipuly: 13*5=65)
We then apply the scale factor to MK to find SK: 60/5=12
(To check we multipuly: 5*12=60)
We now have our answers: RK:13, SK:12
Answer:
1. 20
2. 23
3. 6
Step-by-step explanation:
We have that:
f(x) = 2x
g(x) = x² + 1
f(g(x)) is the composite function of f and g. So
f(g(x)) = f(x²-1) = 2(x²+1) = 2x² + 2
1. f(g(3))
f(g(x)) = 2x² - 2 = 2(3)² + 2 = 18 + 2 = 20
2. f(3)+g(4)
f(3) = 2(3) = 6
g(4) = 4² + 1 = 17
f(3) + g(4) = 6 + 17 = 23
3. f(5) - 2g(1)
f(5) = 2(5) = 10
g(1) = (1)² + 1 = 2
f(5) - 2g(1) = 10 - 2*2 = 10 - 4 = 6
