I'd say <span>c.
Tire tread depth can only be checked by a properly-trained tire expert.
</span>
This option is not true. Anyone with a tread depth gauge can
check tire tread depth. A coin in your pocket can also work. You can insert the
coin with the head showing. The head should always be pointing towards the
tire.
- # Algorithm to find the number of integers greater than 10 in a list
- list = read(list of integers)
- n = len(list)
- count = 0
- For i = 1 to n
- If list[i] > 10:
- count = count + 1
- Endif
- End
- Return count
<h3>
Explanation:</h3>
Then the length of the list is stored in a variable n. A variable count to store the number of integers more significant than 10 is initialized to 0.
- Then, a for-loop is used to iterate over the list. A for-loop is used in this case because every element of the inventory needs to be checked for a value greater than 10.
- In each iteration of the for-loop, the value at the index of the list is checked. If the value is greater than 10, then the counter variable count is incremented by 1.
- The iterations continue till the for-loop ends. At this point, the variable count will be the number of integers greater than 10.
- Note that in case the list does not have any number greater than 10, then the count variable will be 0.
To learn more about it, refer
to brainly.com/question/25311149
#SPJ4
Answer:
#include <iostream>
using namespace std;
void MinMax(int x,int y,int z,int *max,int *min)
{
int big,small;
if((x>y)&&(x>z)) //to check for maximum value
big=x;
else if((y>x)&&(y>z))
big=y;
else
big=z;
if((x<y)&&(x<z)) //to check for minimum value
small=x;
else if((y<x)&&(y<z))
small=y;
else
small=z;
*max=big; //pointer pointing to maximum value
*min=small; //pointer pointing to minimum value
}
int main()
{
int big,small;
MinMax(43,29,100,&big,&small);
cout<<"Max is "<<big<<"\nMin is "<<small; //big and small variables will get value from method called
return 0;
}
OUTPUT :
Max is 100
Min is 29
Explanation:
When the method is called from first three integers maximum will be found using the conditions imposed and maximum value will be found and similarly will happen with the minimum value.
Resposta:
44,76 Kwh
Explicació:
1 cavall = 746 watts
Per tant, 30 cavalls es convertiran en:
30 * 746 = 22380 watts
Temps = 2 hores
La quantitat d'energia consumida s'obté mitjançant la relació:
Energia consumida = Potència * temps
Energia consumida = 22380 watts * 2 hores
Energia consumida = 44760 Wh
A quilowatts (Kwh)
44760 Kwh / 1000 = 44,76 Kwh
I do all you have to do is hook the green screen to your computer and change the back ground so for an example if you are at home you can put yourself in space
