AC is a tangent so by definition, it touches the circle at exactly one point (point C) and forms a right angle at the tangency point. So angle ACO is 90 degrees
The remaining angle OAC must be 45 degrees because we need to have all three angles add to 180
45+45+90 = 90+90 = 180
Alternatively you can solve algebraically like so
(angle OAC) + (angle OCA) + (angle COA) = 180
(angle OAC) + (90 degrees) + (45 degrees) = 180
(angle OAC) + 90+45 = 180
(angle OAC) + 135 = 180
(angle OAC) + 135 - 135 = 180 - 135
angle OAC = 45 degrees
Side Note: Triangle OCA is an isosceles right triangle. It is of the template 45-45-90.
Answer:
Step-by-step explanation:
The point-slope form of an equation of a line:
<em>(x₁, y₁)</em><em> - point on a line</em>
<em>m</em><em> - slope</em>
<em />
We have
Substitute:
Convert to the standard form
<em> use the distributive property</em>
<em>add 5 to both sides</em>
<em>add 4x to both sides</em>
Horizontal, x
straight up and down, y
if you have a 3d plane, z
You can't add the letter so ?
.34 * 250 = g
34 * 2 + 34 * .5 = g
68 + 17 = g
85 = g
85 girls in all of 7th grade
