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Lerok [7]
3 years ago
15

Find the interquartile range of the following data set 3,9,12,4,6,40,25,14,10​

Mathematics
1 answer:
Phoenix [80]3 years ago
8 0
14.5 is the Interquartile range

To find it you take the 75th Percentile (19.5) and subtract it from the 25th Percentile (5)

19.5-5 = 14.5
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Five bags of chips cost $7.
Dvinal [7]

Answer:

1. $1.40 2. $8.40

Step-by-step explanation:

1. 7 divided by 5 is 1.4

2. 1.40 plus $7 equals $8.40

6 0
3 years ago
Read 2 more answers
The school cafeteria seats 250 students. 203 students are already seated. Write and sole an inequality that represents the addit
Nitella [24]

Answer:

An equation that represents the given situation is 203+x=250 and the additional number of students that can be seated is 47

Step-by-step explanation:

Number of students already seated in school cafeteria = 203

Let x be the additional number of students that can be seated

So, Total number of seats available in school cafeteria = 203+x

We are given that the school cafeteria seats 250 students

So, 203+x=250

\Rightarrow x=250-203

\Rightarrow x=47

Hence an equation that represents the given situation is 203+x=250 and the additional number of students that can be seated is 47

6 0
3 years ago
I need help with this ASAP. Thank you for the help
Gre4nikov [31]

Answer:

The relationship is not a function

Step-by-step explanation:

3 0
3 years ago
PLEASE HELP ME ITS DUE IN 1 HOUR
Vadim26 [7]

Answer: Answer:Median: 10.5Lower quartile: 4Upper quartile: 16Explanation:Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 12 (even)Median = Mean of (6)th and (7)th observations = 10 + 11 divided by 2 = 21/2 = 10.5Therefore the median is 10.5.After writing in ascending or descending order the first and last terms justify the lower and upper limits respectively.They are:Lower quartile: 4Upper quartile: 16Question 2.the lengths of 10 pencils, in centimeters:18, 15, 4, 9, 14, 17, 16, 6, 8, 10Type below:_________________Answer:Median: 12Lower quartile: 4Upper quartile: 18Explanation:Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 10 (even)Median = Mean of (5)th and (6)th observations = 10 + 14 divided by 2 = 24/2 = 12Therefore the median is 12.After writing in ascending or descending order the first and last terms justify the lower and upper limits respectively.They are:Lower quartile: 4Upper quartile: 18Question 3.Make a box plot to display the data set in Exercise 2.Type below:_________________Answer:The above box plot represents the lower and upper quartiles, the median.Explanation:Box plot is drawn using the number line and the rectangle which is drawn above it.The ends of the rectangles say about the lower and upper limits and the middle line indicates the median.Question 4.The numbers of students on several teams are 9, 4, 5, 10, 11, 9, 8, and 6. Make a box plot for the data.Type below:_________________Answer: Explanation:Box plot is drawn using the number line and the rectangle which is drawn above it.The ends of the rectangles say about the lower and upper limits and the middle line indicates the median.Therefore the lower and upper quartiles are 4 and 11 respectively.Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 8 (even)Median = Mean of (4)th and (5)th observations = 8 + 9 divided by 2 = 17/2 = 8.5Therefore the median is 8.5.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is the answer ​
Gnom [1K]

Answer:

lol ty for the points

Step-by-step explanation:

4 0
3 years ago
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