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Lerok [7]
3 years ago
15

Find the interquartile range of the following data set 3,9,12,4,6,40,25,14,10​

Mathematics
1 answer:
Phoenix [80]3 years ago
8 0
14.5 is the Interquartile range

To find it you take the 75th Percentile (19.5) and subtract it from the 25th Percentile (5)

19.5-5 = 14.5
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Match the y-coordinates with their corresponding pairs of x-coordinates on the unit circle. the x coordinates to choose from are
vaieri [72.5K]
Of the four x-coordinates to choose only 1/√(11) belongs can belong to the unit circle.

The other three x-coordinates are greater than 1, then they are out of the unit circle.

The unit circle formula is x^2 +y^2 = 1

Then to find the y-coordinate given the x-coordinate you can solve for y from that formula:

y^2 = 1 - x^2

y = (+/-)√(1-x^2)

Substitute the value of x

y = (+/-)√{1 - [1/√(11)]^2} = (+/-) √{(1 - 1/11} =(+/-) √ {(11 -1)/11 =(+/-)√(10/11) ≈ +/- 0.95


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3 years ago
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Dmitry [639]

Answer:

The correct answer is option A.  90°

Step-by-step explanation:

<u>Points to remember</u>

Measure of angles on the semicircle is 90°

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Here <XYZ is on the semicircle that is angle XYZ is a right angle.

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Step-by-step explanation:

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