The distance formula is based on the Pythagorean Theorem:
Distance = Square Root [(X2 - X1)^2<span> + (Y2 - Y1)^</span>2<span>]
</span>Distance = Square Root [(7 -1)^2 + (-7 -1)^2]
Distance = Square Root [ 6^2 + -8^2]Distance = Square Root [ 36 + 64 ]Distance = Square Root [100 ]Distance = 10
Source:http://www.1728.org/distance.htm
Umm no you need to do your own work and do not be asking for answers
Nothing is handed to you ....you need to work HARD to get what you want.
Answer:
okay ans is A(w)=w2+5w-1/8piw2
Answer:
x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)
Step-by-step explanation:
Solve for x:
-8 + x^2 + (x^2 - 8)^2 = 20
Expand out terms of the left hand side:
x^4 - 15 x^2 + 56 = 20
Subtract 20 from both sides:
x^4 - 15 x^2 + 36 = 0
Substitute y = x^2:
y^2 - 15 y + 36 = 0
The left hand side factors into a product with two terms:
(y - 12) (y - 3) = 0
Split into two equations:
y - 12 = 0 or y - 3 = 0
Add 12 to both sides:
y = 12 or y - 3 = 0
Substitute back for y = x^2:
x^2 = 12 or y - 3 = 0
Take the square root of both sides:
x = 2 sqrt(3) or x = -2 sqrt(3) or y - 3 = 0
Add 3 to both sides:
x = 2 sqrt(3) or x = -2 sqrt(3) or y = 3
Substitute back for y = x^2:
x = 2 sqrt(3) or x = -2 sqrt(3) or x^2 = 3
Take the square root of both sides:
Answer: x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)
