Answer:
Step-by-step explanation:
Let's look at the first two, and hopefully you'll be able to figure the rest out:
1. Answer below

The problem asks us to solve for
, so that means we need to get
on one side of the equation by itself. To do so, we will need to divide both sides of the equation by
:


2. Answer below

The problem asks us to solve for
, so that means we need to get
on one side of the equation by itself. To do so, we will need to add
to both sides of equation:


All of the toys would be given out theoretically and 1 extra of the 5 toys would be given out in total.
Answer:
Step-by-step explanation:
C.
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Factoring
<u>Algebra II</u>
- Exponential Rule [Powering]:

- Solving exponential equations
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Solve for </u><em><u>x</u></em>
- Rewrite:

- Set:

- Factor:

- [Division Property of Equality] Divide 3 on both sides:

- [Subtraction Property of Equality] Subtract 3x on both sides:

- [Subtraction Property of Equality] Subtract 6 on both sides:

- [Division Property of Equality] Divide -1 on both sides:
