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shutvik [7]
3 years ago
11

Carlos bought 80 feet of rope for $17.60. He needs 20 more feet. If the unit price is the same how much will he pay for the extr

a 20 feet of rope? Show each step of your solution and explain your reasoning. im in advanced math tho so
Mathematics
1 answer:
Sophie [7]3 years ago
5 0

Answer:

Another 20 feet would be +4.40$

so the total would be $22

Step-by-step explanation:

17.60/4 because 80/20 is 4.

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Solve the following inequality: 10t + 7 , 200 > 21 , 000
Alla [95]

Answer:

t > 1380

Step-by-step explanation:

Subtract 7200 from both sides

10t + 7200 - 7200 > 21000 - 7200

Simplify

10t > 13800

Divide both sides by 10

10t/10 > 13800/10

Simplify

t > 1380

4 0
3 years ago
Tiffany ate ¼ of a pizza. If there were 16 slices of pizza to begin with, how many slices did Tiffany eat?
PIT_PIT [208]

Answer:

she ate 4 slices

Step-by-step explanation:

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2 years ago
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4 students from a class of 15 are going to be chosen to be on the dance committee. Find the number of different 4-person committ
Andrej [43]
We know that
The formula for combinations is
C=n!/[(n-r)!*r!]
where
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r is the number that you choose to arrange

in this problem
n=15 students
r=4 students
C=15!/[(15-4)!*4!]-----> C=15!/[11!*4!]---> (15*14*13*12*11!)/(11!*4*3*2*1)
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7 0
3 years ago
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You are in charge of managing the advertising for a restaurant. You are able to buy up to 62 advertisements a month, and your da
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Answer:

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Step-by-step explanation:

It is given that we should buy at least 5 newspapers for every 3 television ads.

So, after purchasing 3 television ads, we can buy any number of television ads but the number should be greater than 5.

Since, the maximum is 62, we can buy 59 newspaper ads. (Note that we have already bought 3 television ads).

For every 3 television ads, we should buy 5 newspaper ads. So,

For the purchase of 3 television ads, we should buy the minimum of 5 newspaper ads.

For the purchase of 2(3) television ads, we should buy the minimum of 2(5) newspaper ads.

For the purchase of 3(3) television ads, we should buy the minimum of 3(5) newspaper ads.

...

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For the purchase of 7(3) = 21 television ads, we should buy the minimum of 7(5) = 35 newspaper ads.

So, totally 21+35 = 56 ads.

For the remaining 6 ads, if we buy 3 television ads, we should buy 5 newspaper ads.

So, we can buy 2 television ads and 4 newspaper ads.

Hence, we can buy the maximum of 21+2 = 23 television ads.

7 0
3 years ago
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The answer is int(x^2-4x / X = 3).
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