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2 years ago

If a runner was traveling with a velocity of 4 m/s north and had a displacement of 2500 m, how long was he running?

Mathematics

1 answer:

Mademuasel [1]2 years ago

4 0

Answer:

625

Step-by-step explanation:

t= d/s

2500/4

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Answer:

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Step-by-step explanation:

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2 years ago

Which property is illustrated by the following statement? 50pts

Virty [35]

When multiplying numbers, it doesn't matter which number is first or second.

The correct answer is: Commutative Property of Multiplication

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3 years ago

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Make 54/2 to a mixed numbers

Burka [1]

Answer: 27

Step-by-step explanation: Look below for an attached explanation.

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3 years ago

Exercise science researchers collecting data within their state noticed that teens who spend more time streaming videos spend le

Olin [163]

Answer:

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3 years ago

Applying Properties of Exponents In Exercise,use the properties of exponents to simplify the expression.

Mkey [24]

Answer:

$1.~e^{-2} \\2.~e^{\frac{7}{2}}\\3.~e^8\\4.~e^{\frac{-11}{2}}$

Step-by-step explanation:

We have to simplify the given exponential exponents.

Exponential Properties:

$e^0 =1\\e^a.e^b = e^{a+b}\\\\\displaystyle\frac{e^a}{e^b} = e^{a-b}\\\\(e^a)^b = e^{ab}\\\\e^{-a} = \frac{1}{e^a}$

Simplification takes place in the following manner:

$(e^{-3})^\frac{2}{3}\\(e^a)^b = e^{ab}\\=e^{-3\times \frac{2}{3}}\\=e^{-2}$

$(e^4)(e^{\frac{-1}{2}})\\e^a.e^b = e^{a+b}\\=e^{(4+\frac{-1}{2})} \\= e^{\frac{7}{2}}$

$(e^{-2})^{-4}\\(e^a)^b = e^{ab}\\= e^{-2\times -4}\\=e^8$

$(e^{-4})(e^{\frac{-3}{2}})\\e^a.e^b = e^{a+b}\\=e^{(-4+\frac{-3}{2})} \\= e^{\frac{-11}{2}}$

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3 years ago