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miss Akunina [59]
3 years ago
12

What is the measure of the indicated angle ?

Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0

Answer:

The measure of the indicated angle is 72°

Step-by-step explanation:

If two parallel lines intersected by a transversal, then

  • There are pairs of corresponding angles equal in measures
  • There are pairs of alternate interior angles equal in measures
  • There are pairs of alternate exterior angles equal in measures
  • There are pairs of adjacent interior angles that are supplementary

In the given figure

∵ There are two parallel lines intersected by a transversal

∵ The angle of measure 108° and the indicated angle are adjacent

   interior angles

∴ They are supplementary

∵ The sum of the measures of supplementary angles is 180°

∴ 108 + indicated angle = 180

→ Subtract 108 from both sides

∴ The measure of the indicated angle = 72°

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Bezzdna [24]

Answer:

The product of 10 and a number is = 10x Twice that number means 2x 36 less than twice that number= 2x-36. It is given that....The product of 10 and a number is the same as 36 less twice that same number

Step-by-step explanation:

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3 years ago
What is the solution set of x2 + y2 = 26 and x − y = 6? A. {(5, -1), (-5, 1)} B. {(1, 5), (5, 1)} C. {(-1, 5), (1, -5)} D. {(5,
Rus_ich [418]
He two equations given are
x^2 + y^2 = 26
And
x - y = 6
x = y +6
Putting the value of x from the second equation to the first equation, we get
x^2 + y^2 = 26
(y + 6) ^2 + y^2 = 26
y^2 + 12y + 36 + y^2 = 26
2y^2 + 12y + 36 - 26 = 0
2y^2 + 12y + 10 = 0
y^2 + 6y + 5 = 0
y^2 + y + 5y + 5 = 0
y(y + 1) + 5 ( y + 1) = 0
(y + 1)(y + 5) = 0
Then 
y + 1 = 0
y = -1
so x - y = 6
     x + 1 = 6
x = 5
Or
y + 5 = 0
y = - 5
Again x = 1
So the solutions would be (-1, 5), (1 , -5). The correct option is option "C".

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142 x 12 in algorithm standard<br> and in area model
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Answer:

0333

Step-by-step explanation:

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000

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(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.
Andreyy89

\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1

Recall that

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

Your sums start at i=3, so in order to apply these formulas directly, you need to compensate for the missing first two terms:

\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8

\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52

\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}

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Answer:

Step-by-step explanation:

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