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LekaFEV [45]
3 years ago
10

142 x 12 in algorithm standard and in area model

Mathematics
1 answer:
Katen [24]3 years ago
4 0

Answer:

0333

Step-by-step explanation:

00

000

0000

1112222

______

11122222 ans

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Twice c is at least 19
Sliva [168]
<h3><u>The value of c is greater than or equal to the value 9.5</u></h3>

2c ≥ 19

We can treat this inequality like a standard algebraic equation.

<em><u>Divide both sides by 2.</u></em>

c ≥ 9.5

7 0
3 years ago
What is the rate of change of a line that passes through the points (-3,5) and (2,-1)?
lara [203]

Answer:

3/4

Step-by-step explanation:

The slope of the line is

m = (y2-y1)/(x2-x1)

   = (-2--5)/(6-2)

   = (-2+5)/(6-2)

    =3/4

6 0
3 years ago
Identify the domain and range of the function graphed below. <br><br><br><br>​
Vladimir [108]

Answer:

Domain: (-∞, 4]

Range: [0, ∞)

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)
  • Range is the set of y-values that are outputted by function f(x)

Step-by-step explanation:

According to the graph, we see the line's x-value span from negative infinity to 4. Since 4 is closed dot, it is inclusive in the domain:

(-∞, 4] or x ≤ 4

According to the graph, we see the line's y-value span from 0 to infinity. Since 0 is closed dot, it is inclusive in the range:

[0, ∞) or y ≥ 0

8 0
3 years ago
RectangleABCD has vertices at A(– 3, 1),B(– 2, – 1),C(2, 1), andD(1, 3). What is the area, in square units, of this rectangle? A
Anna [14]

Answer:

Option A. 10\ units^{2}

Step-by-step explanation:

we know that

The area of the rectangle is equal to

A=LW

where

L is the length of rectangle

W is the width of rectangle

we have

A(-3,1),B(-2,-1),C(2,1),D(1,3)

Plot the vertices

see the attached figure

L=AD=BC

W=AB=DC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

<em>Find the distance AD</em>

A(-3,1),D(1,3)

substitute in the formula

AD=\sqrt{(3-1)^{2}+(1+3)^{2}}

AD=\sqrt{(2)^{2}+(4)^{2}}

AD=\sqrt{20}

AD=2\sqrt{5}\ units

<em>Find the distance AB</em>

A(-3,1),B(-2,-1)

substitute in the formula

AB=\sqrt{(-1-1)^{2}+(-2+3)^{2}}

AB=\sqrt{(-2)^{2}+(1)^{2}}

AB=\sqrt{5}

AB=\sqrt{5}\ units

Find the area

A=(2\sqrt{5})*(\sqrt{5})=10\ units^{2}

4 0
3 years ago
PLEASEEEE I NEED A ANSWER ASAP!!!!
Vsevolod [243]

((60 * c) + 3300 ≤ 24000

60c ≤ 24000 - 3300

60c ≤ 20700

c ≤ 20700  / 60

c ≤ 345

7 0
3 years ago
Read 2 more answers
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