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2 years ago

Help me this and show your work

Mathematics

1 answer:

krek1111 [17]2 years ago

6 0

First set 2n-1=4n+5 and solve for n. once you have n plug it back into each equation and then multiply those two together. Do the same to n-3 and 2n+1. Once you get the answer to both subtract them

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Help me please my math didn’t teach me this!

Airida [17]

Sorry I don’t know it right now but I can help you with some thing else

8 0

2 years ago

Find the area of the partial circle. use 3.14 for pi.

nignag [31]

Radius=1cm=r

Thats a semi circle

Area

πr²/2
π(1)²/2
π/2
3.14/2
1.57cm²

6 0

1 year ago

The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5 . Suppose 49 golfers p

Nadya [2.5K]

Answer:

The probability that the average score of the 49 golfers exceeded 62 is 0.3897

Step-by-step explanation:

The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5

$\mu = 61$

$\sigma = 3.5$

We are supposed to find he probability that the average score of the 49 golfers exceeded 62.

Formula : $Z=\frac{x-\mu}{\sigma}$

$Z=\frac{62-61}{3.5}$

$Z=0.285$

Refer the z table for p value

p value = 0.6103

P(x>62)=1-P(x<62)=1-0.6103=0.3897

Hence the probability that the average score of the 49 golfers exceeded 62 is 0.3897

7 0

3 years ago

I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha

Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = $\frac{\theta}{360}(\pi r^{2})$

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = $\frac{60}{360}(\pi) (10^{2})$

= 52.36 in²

Area of equilateral triangle BCD = $\frac{\sqrt{3} }{4}(\text{Side})^2$

= $\frac{\sqrt{3} }{4}(10)^2$

= $25\sqrt{3}$ in²

= 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

= 9.06 in²

Area of sector CAD = $\frac{90}{360}(\pi)(\sqrt{50})^2$

= 39.27 in²

Area of right triangle CAD = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(\text{AC})(\text{AD})$

= $\frac{1}{2}(\sqrt{50})(\sqrt{50})$

= 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

= 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

= 23.33 in²

8 0

2 years ago

COOKING Franklin is cooking a 3-pound turkey breast for 6 people. If the number of pounds of turkey varies directly with the num

Gwar [14]

<u>Answer-</u>

2, 4, and 8 people will need 1, 2, 4 pounds of turkey respectively.

<u>Solution-</u>

Given in the question, number of pounds of turkey varies directly with the number of people, i.e as the number of people increases or decreases, the pound of turkey also increases or decreases.

Taking,

x = number of people,

y = pounds of turkey.

This condition can be represented as,

$\Rightarrow y\ \alpha \ x\\\Rightarrow y=kx$