2 years ago

Help me this and show your work

1 answer:

6 0

First set 2n-1=4n+5 and solve for n. once you have n plug it back into each equation and then multiply those two together. Do the same to n-3 and 2n+1. Once you get the answer to both subtract them

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What would the exponent be when 9540000 is written in scientific notation?

natka813 [3]

Answer:

Step-by-step explanation:

9.54 x 10^6

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3 years ago

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kvv77 [185]

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3 years ago

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Find the zeros of the function h(x)=x^2-5x-50 by factoring

lukranit [14]

$h(x)=x^2-5x-50=x^2-5x-25-25=x^2-25-5x-25\\\\=(x^2-25)-(5x+25)=(x^2-5^2)-5(x+5)\\\\=(x-5)\underline{(x+5)}-5\underline{(x+5)}=(x+5)(x-5-5)=(x+5)(x-10)\\\\Answer:Zeros\ are\ x=-5\ and\ x=10.$

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3 years ago

Approximate the real zeros of f(x)= 2x^3 - 4x^2 - 3 to the nearest tenth.

Scrat [10]

Answer:

b.2.3

Step-by-step explanation:

f(x)= 2x^3 - 4x^2 - 3

see graph below

only x intercept is 2.287

6 0

2 years ago

Plsss help !!

Gennadij [26K]

Answer:

carnation $2.50; rose $3.00

Step-by-step explanation:

Let c = price of 1 carnation.

Let r = price of 1 rose.

3c + 5r = 22.5

3c + 2r = 13.50

Subtract the se3cond equation from the first equation.

3r = 9

r = 3

Now substitute r = 3 in the first equation and solve for c.

3c + 5r = 22.5

3c + 5(3) = 22.5

3c = 7.5

c = 2.5

Answer: carnation $2.50; rose $3.00

5 0

2 years ago