All categories

3 years ago

You ride the subway about 45 times per month. should you buy the monthly pass

Mathematics

1 answer:

exis [7]3 years ago

3 0

Is it cheaper then without it? If so you should

You might be interested in

Anyone please gives me the correct answer to this problem on Khan Academy. The assignment is due tomorrow, and I don't want to f

spin [16.1K]

Answer:

(-2,-2) and (-7,1)

Step-by-step explanation:

I can't see i am trying

6 0

2 years ago

How to cross multiple 3/5 by 10

Vika [28.1K]

Here is you're answer:

In order to cross multiply you have to multiply the numerator and denominator of the first fraction by the bottom number of the second fraction and see if the equation is still true:

$\frac{3}{5} \times 10$
$\frac{3}{5} \times \frac{10}{1}$
$3 \times 1 = 5 \times 10$
Solve if you like:
$3 \times 1 = 3$
$5 \times 10 = 50$
$= \frac{4}{50}$

Therefore you're answer is "3 × 1 = 5 × 10."

Hope this helps!

4 0

3 years ago

A cube has a volume of 64 cubic feet. The surface area of the cube is?

oee [108]

Answer:

The surface area is A≈96ft²

8 0

3 years ago

Read 2 more answers

Solve. Good luck! Please do not try to google this.

Elena L [17]

$\frac{x^{2} + x - 2}{6x^{2} - 3x} = \sqrt{2x} + \frac{3x^{2}}{2}$
$\frac{x^{2} + 2x - x - 2}{3x(x) - 3x(1)} = \frac{2\sqrt{2x}}{2} + \frac{3x^{2}}{2}$
$\frac{x(x) + x(2) - 1(x) - 1(2)}{3x(x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{x(x + 2) - 1(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$3x(2x - 1)(2\sqrt{2x} + 3x^{2}) = 2(x + 2)(x - 1)$
$3x(2x(2\sqrt{2x} + 3x^{2}) - 1(2\sqrt{2x} + 3x^{2}) = 2(x(x - 1) + 2(x - 1))$
$3x(2x(2\sqrt{2x}) + 2x(3x^{2}) - 1(2\sqrt{2x}) - 1(3x^{2})) = 2(x(x) - x(1) + 2(x) - 2(1)$
$3x(4x\sqrt{2x} + 6x^{3} - 2\sqrt{2x} - 3x^{2}) = 2(x^{2} - x + 2x - 2)$
$3x(4x\sqrt{2x} - 2\sqrt{2x} + 6x^{3} - 3x^{2}) = 2(x^{2} + x - 2)$
$3x(4x\sqrt{2x}) - 3x(2\sqrt{2x}) + 3x(6x^{3}) - 3x(3x^{2}) = 2(x^{2}) + 2(x) - 2(2)$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} + 18x^{4} - 9x^{3} = 2x^{2} + 2x - 4$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} = -18x^{4} + 9x^{3} + 2x^{2} + 2x - 4$
$6x\sqrt{2x}(2x) - 6x\sqrt{2x}(1) = -9x^{3}(2x) - 9x^{3}(-1) + 2(x^{2}) + 2(x) - 2(2)$
$6x\sqrt{2x}(2x - 1) = -9x^{3}(2x - 1) + 2(x^{2} + x - 2)$

5 0

4 years ago

75 students in a kindergarten. 40% of them can read. how many can read?

Paul [167]

Answer:

Step-by-step explanation:

75 times .40 = 30

8 0

3 years ago

Read 2 more answers