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UkoKoshka [18]
3 years ago
9

Point R is on line segment QS

Mathematics
1 answer:
igomit [66]3 years ago
5 0

Answer: 8

Step-by-step explanation:

QS = RS + QR

3x = 2x + 3x-8

3x = 5x - 8

8 = 2x

8/2 = x

4 = x

RS = 2x = 2(4) = 8

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I need help with please
gregori [183]

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2 years ago
Find the standard form of the circle x2 + y2 – 6x + 10y + 24 = 0 by completing the square.
hichkok12 [17]

Answer:

(x-3)^2+ (y+5)^2=10

Step-by-step explanation:

Given the equation of the circle: x^2 + y^2 - 6x + 10y + 24 = 0

We wish to express it in a Standard form:

We begin by re-arranging:

x^2 - 6x + y^2  + 10y  = - 24

Next, divide the coefficient of x by 2, square it and add it to both sides.

Do the same for y.

x^2 - 6x +(-3)^2+ y^2  + 10y+5^2  = - 24+(-3)^2+5^2

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This is the standard form.

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3 years ago
What is 1.56 rounded to the nearest tenth
jeka57 [31]

Answer:

1.6

Step-by-step explanation:

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