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Nookie1986 [14]
2 years ago
11

meteroloogist track severe stoms using Doppler radar. A polar grid is used to measure distances as the storms progress. If the c

enter of the radar screen is the origin and each ring is 10 miles farther from the center, what is the equation of the fourth ring
Mathematics
1 answer:
FinnZ [79.3K]2 years ago
5 0

Answer:

$(x-h)^2+(y-k)^2= (r+ 40 )^2$  

Step-by-step explanation:

It is given that a meteorologist is using a Doppler radar to find out the distance of the storm as it passes using a polar grid.

The origin of the radar screen is its center.

And the distance between each ring is 10 miles from the center.

So let :

r = radius

h and k = be the coordinates of the center.

So the equation of a circle is :

$(x-h)^2+(y-k)^2= r^2 $

Now the equation of the fourth circle when the radius changes by 10 miles is :

$(x-h)^2+(y-k)^2= (r+ 40 )^2$  

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Sylvies age is 5 years less than half of katies age. if sylvie is 11 years old, what is katies age
UkoKoshka [18]
Katie is 32 years old
add 5 to 11 and multiply 16 by 2 to get 32
6 0
2 years ago
What is the measurement of Angle JKL? *
nataly862011 [7]

Answer:

Option (1)

Step-by-step explanation:

From the triangles given in the picture,

Since, JK ≅ KL [Given]

JM ≅ ML [Given]

KM ≅ KM [Reflexive property of congruence]

ΔJMK ≅ ΔLMK [SSS property of congruence]

Therefore, ∠JKM ≅ ∠LKM [CPCTC]

(2x + 5) = (3x - 6)

3x - 2x = 5 + 6

x = 11

m∠JKL = m∠JKM + m∠LKM

            = (2x + 5) + (3x - 6)

            = 5x - 1

            = 5(11) - 1

             = 54

Option (1) will be the answer.

4 0
2 years ago
If electricity power failures occur according to a Poisson distribution with an average of 3 failures every twenty weeks, calcul
Wittaler [7]

Answer:

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

3 failures every twenty weeks

This means that for 1 week, \mu = \frac{3}{20} = 0.15

Calculate the probability that there will not be more than one failure during a particular week.

Probability of at most one failure, so:

P(X \leq 1) = P(X = 0) + P(X = 1)

Then

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.15}*0.15^{0}}{(0)!} = 0.8607

P(X = 1) = \frac{e^{-0.15}*0.15^{1}}{(1)!} = 0.1291

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.8607 + 0.1291 = 0.9898

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

6 0
2 years ago
Mikey bought 4 of the 500 raffle tickets sold to
Zina [86]

Answer:

4/500

Step-by-step explanation:

6 0
3 years ago
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Answer:

p+1.50=b

Step-by-step explanation:

Hope it helps (;

7 0
3 years ago
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