9514 1404 393
Answer:
top down: ∞, 0, 1, 0, ∞
Step-by-step explanation:
The equation will have infinite solutions when the left side and right side simplify to the same expression. This is the case for the first and last expressions listed.
2(x -5) = 2(x -5) . . . . expressions are already identical
x +2(x -5) = 3(x -2) -4 ⇒ 3x -10 = 3x -10 . . . the same simplified expression
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The equation will have no solutions when the x-coefficients are the same, but there are different added constants.
5(x +4) = 5(x -6) ⇒ x +4 = x -6 . . . not true for any x
4(x -2) = 4(x +2) ⇒ x -2 = x +2 . . . not true for any x
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The equation will have one solution when coefficients of x are different.
5(x +4) = 3(x -6) ⇒ 2x = -38 ⇒ x = -19
To determine The probability of both of these occurring, you would multiply the probability of each together. So, there is a 1/7 chance of the first salesman getting the right key, and 1/6 chance of the second salesman getting the right key. 1/7 x 1/6= 1/42 chance of both occurring.
Answer:
Voir ci-dessous.
Step-by-step explanation:
1.
OA/OD = 36/64 = 9/16
OB/OC = 27/48 = 9/16
m<AOB = m<COD
triangle AOB ~ trianlge DOC
m<BAO = m<CDO
AB || CD
2.
AB/CD = OA/OD
AB/80 = 36/64
AB/80 = 9/16
16AB = 9 × 80
AB = 9 × 5
AB = 45
AB = 45 cm
3.
AB = 45
BC = OC + OB = 48 + 27 = 75
AB² + AC² = BC²
45² + AC² = 75²
AC² = 5625 - 2025
AC = √3600
AC = 60 cm
hauteur = 5 × 2 cm + 4 × 60 cm
hauteur = 10 cm + 240 cm
hauteur = 250 cm
Answer:
5091 Km/hr and 505 km/hr
Step-by-step explanation:
Speed = Distance / Time
Let the speed of first automobile be 'x' and that of the second be 'y'
Since speed of one is 10 times greater than the other. therefore;
⇒ x = 10 y
also let time for faster automobile be 'T' and time for slower auto mobile be 't'
Since first arrive one hour earlier than second, therefore;
⇒ t = T + 1
⇒ For first automobile; 
; substituting for 'x' and 'T'. Therefore;
⇒ 
⇒ For Second automobile; 
⇒ 
⇒ 
⇒ 5600 + 
= 560
⇒ 5600 - 560 = -
⇒ t = 1.11 hr
also ; T = 1.11 - 1 = 0.11 hr
Speed of 1st auto = 560/0.11 = 5091 km /hr
Speed of 2nd auto = 560/1.11 = 505 km/hr
