#21)
<span>Using Pythagorean Theorem a^2 + b^2 = c^2
so
</span>a^2 = c^2 - b^2
x^2 = 42^2 - 38^2
x^2 = 1764 - 1444
x^2 = 320
x =√320
x = √(64 * 5)
x = 8√5
27 prime factors: 9*3 prime factors of 9: 3*3
117 prime factors: 39*3 prime factors of 39: 13*3
that would make 3 the greatest common factor. for the other ones break down the numbers into the smallest amount and see which largest factor both numbers have in common.
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I believe it is 510 cm because a meter equals 100 cm so 210 cm times 2 equals 410 cm then multiply 45 times 2 and get 90 cm then add 410 plus 90 and get 510 cm.
So the sides ML and MN are exactly the same. Your equation would look something like this...
3x = x + 10
You first subtract x from both sides to isolate the variable.
2x = 10
Divide 2 from both sides.
x = 5
5 is the length of MN.
I hope this helps love! :)
Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
