
![\bf \sqrt{n}< \sqrt{2n+5}\implies \stackrel{\textit{squaring both sides}}{n< 2n+5}\implies 0\leqslant 2n - n + 5 \\\\\\ 0 < n+5\implies \boxed{-5 < n} \\\\\\ \stackrel{-5\leqslant n < 2}{\boxed{-5}\rule[0.35em]{10em}{0.25pt}0\rule[0.35em]{3em}{0.25pt}2}](https://tex.z-dn.net/?f=%5Cbf%20%5Csqrt%7Bn%7D%3C%20%5Csqrt%7B2n%2B5%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bsquaring%20both%20sides%7D%7D%7Bn%3C%202n%2B5%7D%5Cimplies%200%5Cleqslant%202n%20-%20n%20%2B%205%20%5C%5C%5C%5C%5C%5C%200%20%3C%20n%2B5%5Cimplies%20%5Cboxed%7B-5%20%3C%20n%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B-5%5Cleqslant%20n%20%3C%202%7D%7B%5Cboxed%7B-5%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D0%5Crule%5B0.35em%5D%7B3em%7D%7B0.25pt%7D2%7D)
namely, -5, -4, -3, -2, -1, 0, 1. Excluding "2" because n < 2.
Answer:
Opposite sides must be congruent.
Step-by-step explanation:
Given is a picture of a quadrilateal ABCD
We have to prove that this is a parallelogram.
Recall the properties of parallelogram as
i) diagonals bisect each other
ii) opposite sides parallel
iii) opposite sides congruent
or iv) one pair of opposite sides equal and parallel
We have hence to get opposite sides congruent
So last option is right
I don’t know how old this is but hopefully I’m not too late it’s 17 7+10=17 it is NOT 70 ♀️
Step-by-step explanation:
∫ (sec x − tan x) dx
∫ sec x dx + ∫ -tan x dx
∫ (sec²x + sec x tan x) / (sec x + tan x) dx + ∫ (-sin x / cos x) dx
ln(sec x + tan x) + ln(cos x) + C
Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The value of x is 
Step-by-step explanation:
From the question we are told that
The length of the vertical length is 
The length of the base leg is L = 330 + d units
The length of the bisecting line segment is h
The base angle is 
The angle between d and line segment is 
For the first angle

=> 
For the whole big triangle

=> 
So equating the both d

Substitute values



