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hodyreva [135]
3 years ago
13

Porfa es para un examen

Mathematics
1 answer:
lakkis [162]3 years ago
4 0

Answer:

Tu examen es para potos

Step-by-step explanation:

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Which best describes the expression 4(y+6)
zavuch27 [327]
4y + 24 is the answer to that equation. 
4 0
3 years ago
Read 2 more answers
Mohon bantuannya kawan
Natasha_Volkova [10]

Answer:

hope this helps you

God bless you

8 0
2 years ago
Please help me with this problem.
Alik [6]

We're going to use the equation given but let's first make sure we understand what the equation IS saying:

Area of a kite= [(1st diagonal) × (2nd diagonal)]/2

Now, let's find the 2 diagonals. In the case of kite shapes one of the diagonals is the line that goes from W to Y and the other is the line going from X to Z. In a kite they will always cross (no matter their lengths).

Now that we know the diagonals we can add the lengths that are given for each line to know what to multiply.

Line W to Y: 20+12= 32

Line X to Z: 12+12= 24

Now let's plug these numbers into the equation (it doesn't matter the order of the diagonals because we're just gonna be multiplying them either way!)

So...

(32×24)/2= 384 units squared (because it is area)

8 0
3 years ago
Dharma and Jorge are looking at cell phone plans. A
riadik2000 [5.3K]

Answer:

Dharma and Jorge should purchase a group plan.

They could save $9.55

Step-by-step explanation:

A group plan will cost an average of $135.95 per month.

An individual plan will cost an average of $72.75 per month.

Two individual plans will cost an average of

\$72.75\cdot 2=\$145.50

per month.

Since $145.50 > $135.95,  Dharma and Jorge should purchase a group plan.

They could save

\$145.50-\$135.95=\$9.55

4 0
3 years ago
Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am
zheka24 [161]

SOLUTION

We have been given the equation of the decay as

\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}

So we are looking for the time

Plugging the values into the equation, we have

\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}

Taking Ln of both sides, we have

\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}

Hence the answer is 4308 to the nearest year

8 0
1 year ago
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