The sixth grade runs a bake sale for 55 hours and makes $170.
So in one hour, they made 170/55 = 3.09 dollars.
Rate: $3.09/h
The seventh grade sets up a dunking booth for 44 hours and makes $112.
So in one hour, they made 112/44 = 2.54 dollars.
Rate: $2.54/h
The eight grade has a car wash and makes $192 in 66 hours.
So in one hour, they made 192/66 = 2.90 dollars.
Rate $2.90/h
3.09 > 2.90 > 2.54
So R(6th) > R(8th) > R(7th)
Which means that the sixth grade has the highest rate for raising money.
Hope this helps! :)
F(X) = 2x + 1
Replace f(x) with y:
Y = 2x+ 1
Switch variables:
X = 2y + 1
Solve for Y:
Subtract 1 from both sides:
X- 1 = 2y
Divide both sides by 2:
X-1 / 2 = y
Rewrite so y is in the left side:
Y = x-1 / 2
Replace y with f^-1(x):
F^-1(x) = x-1 / 2
This can also be written as x/2 - 1/2
<span>B. 1 + 1 = 2
C. 2 + 0 = 2</span>
Answer:
Step-by-step explanation:
The graph is generally increasing. Thus, as the weight increases, the cost increases with it.
