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allsm [11]
4 years ago
12

8)

Mathematics
2 answers:
ira [324]4 years ago
4 0
You can add both units together: Namely you can add 5.15 to 3.04 = which equals to 8.19 and the average of 108 + 180 = 360/2
which means its an averige of 180.
so the correct anwser is C) 8.19 x 108 people
Cloud [144]4 years ago
3 0

Answer:

The answer is 8.19 x 108 (letter C).

Step-by-step explanation:

In order to determine the answer, we have to know about factorization.

In any math expression, sometimes there are equal terms. A term is just a variable and a coefficient. Also a variable may be just a number.

When there are two equal numbers or two equal variables, we can factorize them. This factor will multiply other expression inside in the parentheses.

In this case, we have two numbers, 5.15 x 108 and 3.04 x 108. Both numbers have the 108 equal. Also, we have to add the North America population with the South America population.

Factoring by 108:

5.15*108+3.04*108\\108*(5.15+3.04)\\8.19*108

Finally, the answer is 8.19 x 108 (letter C).

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In a science class of twenty-eight students. 12 boys and girls. On a unit test, 4 boys and 10 girls made an A grade. A student i
Wewaii [24]

Answer:

Step-by-step explanation:

probability of choosing a boy = 12 / 28 = 3 / 7

in % = 3 / 7 x 100 = 42,86%

probability of choosing an a student = (4 + 10) / 28 = 14 / 28 = 1 / 2

in % = 1 / 2 x 100 = 50%

6 0
3 years ago
Explain why the absolute value of a number will never be negative
aleksandr82 [10.1K]
The absolute value of a number will never be negative because absolute value is the distance from zero, so it will always be positive. For example, you can't be -6 away from 0, you are 6 away from 0.
7 0
3 years ago
Read 2 more answers
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sineoko [7]

Is there a picture for this I could maybe help

7 0
3 years ago
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Umeko and Clemente are simplifying the problem below, who was wrong? Explain the error.
lapo4ka [179]
\log_76+\log_73-\log_72 \\ =\log_7(6\times 3)-\log_72\\  =\log_718-\log_72 \\=\log_7 \frac{18}{2}  \\ =\log_79
8 0
4 years ago
Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even. what kind of proof did you
scoray [572]
Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n

Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
6 0
3 years ago
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