Answer:
5/30 = 1/6
Step-by-step explanation:
We have the following information available in this question
Total t shirts I. This laundry basket = 30
15 t shirts = red
5 tshirts = blue
Then white t-shirts would be = 30-(5+15)
= 20
The probability of picking blue t shirt =
Total number of blue t-shirt divided by total number of t shirts
= 5/30
= 1/6 when reduced further as a fraction
Answer:
d) 5 lollipops each and 3 left over
Step-by-step explanation:
To find out how many each of them get, you need to find the total amount of lollipops to be shared equally.
Total No. of lollipops = 3 + 5 + 7 + 4 + 9
= 28
No. of lollipops each of them get = 28 ÷ 5
= 5 R3
(To find the remainder of something, you have to know how much is the quotient (which is 5 in this case), multiply it by the divisor (which is also 5 in this case) then minus that number from the total (which is 28 in this case) )
Additional working:
5 × 5 = 25
28 - 25 = 3 (remainder)
Use the chain rule:
<em>y</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)
<em>y'</em> = sec²(<em>x</em> ² - 5<em>x</em> + 6) × (<em>x</em> ² - 5<em>x</em> + 6)'
<em>y'</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
Perhaps more explicitly: let <em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6, so that
<em>y(x)</em> = tan(<em>x</em> ² - 5<em>x</em> + 6) → <em>y(u(x))</em> = tan(<em>u(x)</em> )
By the chain rule,
<em>y'(x)</em> = <em>y'(u(x))</em> × <em>u'(x)</em>
and we have
<em>y(u)</em> = tan(<em>u</em>) → <em>y'(u)</em> = sec²(<em>u</em>)
<em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6 → <em>u'(x)</em> = 2<em>x</em> - 5
Then
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>u</em>)
or
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
as we found earlier.
Answer:
A
Step-by-step explanation: democracy is the best form of ruling the masses

<h2>
Explanation:</h2>

In this exercise, we have two cases and both will be polynomial functions with degree 3 because we have three real roots in each case. So:
<h3>First.</h3>
The roots are:

So we can write this polynomial functions as the product of linear factors:

Since we have to write it in standard form, let's expand:

<h3>Second.</h3>
The roots are:

Writing the polynomial function as the product of linear factors:

<h2>Learn more:</h2>
Degree of polynomial functions: brainly.com/question/5451252
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