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kkurt [141]
3 years ago
11

Okay guys I'm not very good at word problems, but here's my question:

Mathematics
1 answer:
allsm [11]3 years ago
8 0

Answer:

54 students

Step-by-step explanation:

331 - 7 = 324

324 divided by 6 = 54

Hope this helps :D

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A laundry basket has 30 t-shirts in it. The basket has 15 red shirts, 5 blue shirts and the rest are white. What is the probabil
4vir4ik [10]

Answer:

5/30 = 1/6

Step-by-step explanation:

We have the following information available in this question

Total t shirts I. This laundry basket = 30

15 t shirts = red

5 tshirts = blue

Then white t-shirts would be = 30-(5+15)

= 20

The probability of picking blue t shirt =

Total number of blue t-shirt divided by total number of t shirts

= 5/30

= 1/6 when reduced further as a fraction

8 0
3 years ago
Urgent Please help!!!!!!!
MakcuM [25]

Answer:

d) 5 lollipops each and 3 left over

Step-by-step explanation:

To find out how many each of them get, you need to find the total amount of lollipops to be shared equally.

Total No. of lollipops = 3 + 5 + 7 + 4 + 9

                                   = 28

No. of lollipops each of them get = 28 ÷ 5

                                                       = 5 R3

(To find the remainder of something, you have to know how much is the quotient (which is 5 in this case), multiply it by the divisor (which is also 5 in this case) then minus that number from the total (which is 28 in this case) )

Additional working:

5 × 5 = 25

28 - 25 = 3 (remainder)

5 0
3 years ago
Read 2 more answers
Differentiate<br>y=tan (x^2-5x+6)​
slavikrds [6]

Use the chain rule:

<em>y</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)

<em>y'</em> = sec²(<em>x</em> ² - 5<em>x</em> + 6) × (<em>x</em> ² - 5<em>x</em> + 6)'

<em>y'</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)

Perhaps more explicitly: let <em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6, so that

<em>y(x)</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)   →   <em>y(u(x))</em> = tan(<em>u(x)</em> )

By the chain rule,

<em>y'(x)</em> = <em>y'(u(x))</em> × <em>u'(x)</em>

and we have

<em>y(u)</em> = tan(<em>u</em>)   →   <em>y'(u)</em> = sec²(<em>u</em>)

<em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6   →   <em>u'(x)</em> = 2<em>x</em> - 5

Then

<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>u</em>)

or

<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)

as we found earlier.

5 0
3 years ago
The philosophers Socrates, Plato, and Aristotle shared what common belief? A) democracy is the best form of ruling the masses B)
GenaCL600 [577]

Answer:

A

Step-by-step explanation: democracy is the best form of ruling the masses

8 0
3 years ago
Read 2 more answers
Write a polynomial function with the given zeros. multiply the terms (write in standard form).
ryzh [129]

1) \ f(x)=x^3-3x-2 \\ \\ 2) \ g(x)=x^3-x^2-6x

<h2>Explanation:</h2>

A \ \mathbf{polynomial \ function} \ of \ x \ with \ degree \ n \ is \ given \ by:\\ \\ f(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\ldots +a_{2}x^{2}+a_{1}x+a_{0} \\ \\ where \ n \ is \ a \ nonnegative \ integer \ and \ a_{n}, a_{n-1}, \ldots a_{2}, a_{1}, a_{0} \\ with \ a_{n}\neq 0

In this exercise, we have two cases and both will be polynomial functions with degree 3 because we have three real roots in each case. So:

<h3>First.</h3>

The roots are:

x= -1, -1, 2

So we can write this polynomial functions as the product of linear factors:

f(x)=(x-(-1))(x-(-1))(x-2) \\ \\ f(x)=(x+1)^2(x-2)

Since we have to write it in standard form, let's expand:

f(x)=(x+1)^2(x-2) \\ \\ \\ By \ property: \\ \\ (a+b)^2=a^2+2ab+b^2 \\ \\ \\ f(x)=(x^2+2x+1)(x-2) \\ \\ f(x)=x^3+2x^2+x-2x^2-4x-2 \\ \\ \\ Combine \ like \ terms: \\ \\ x^3+(2x^2-2x^2)+(x-4x)-2 \\ \\ \\ \boxed{f(x)=x^3-3x-2}

<h3>Second.</h3>

The roots are:

x= -2, 0, 3

Writing the polynomial function as the product of linear factors:

g(x)=(x-(-2))(x-0)(x-3) \\ \\ g(x)=(x+2)x(x-3) \\ \\ g(x)=x(x+2)(x-3) \\ \\ \\ Distributive \property: \\ \\ g(x)=x(x^2-3x+2x-6) \\ \\ g(x)=x(x^2-x-6) \\ \\ \\ Distributive \ property \ again: \\ \\ \boxed{g(x)=x^3-x^2-6x}

<h2>Learn more:</h2>

Degree of polynomial functions: brainly.com/question/5451252

#LearnWithBrainly

7 0
3 years ago
Read 2 more answers
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