Question

What are the excluded values of x for x + 1/ x^2-1

Answer 1

The excluded values of x are $x=1$ and $x=-1$

Explanation:

The given expression is $\frac{x+1}{x^2-1}$

The excluded values are the values in the fraction which makes the denominator equal to 0.

Thus, from the definition of excluded values, let us equate the denominator to 0.

Hence, we have,

$x^{2} -1=0$

Adding both sides of the equation by 1, we get,

$x^{2} =1$

Taking square root on both sides of the equation, we get,

$x=\sqrt{1}$

Simplifying, we get,

$x=\pm1$

Thus, the excluded values of x are $x=1$ and $x=-1$