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4 years ago

Really need help writing an inequality in algebra PLEASE HELP ME!!!! PLEASE PLEASE PLEASE

Mathematics

1 answer:

almond37 [142]4 years ago

3 0

You gotta write the question down first for us to see what it is

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A simulation was conducted using 10 fair six-sided dice, where the faces were numbered 1 through 6. respectively. All 10 dice we

kompoz [17]

Answer:

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

Step-by-step explanation:

Here, the random experiment is rolling 10, 6 faced (with faces numbered from 1 to 6) fair dice and recording the average of the numbers which comes up and the experiment is repeated 20 times.So, here sample size, n = 20 .

Let,

$X_{ij}$ = The number which comes up on the ith die on the jth trial.

∀ i = 1(1)10 and j = 1(1)20

Then,

$E(X_{ij})$ = $\frac {1 + 2 + 3 + 4 + 5 + 6}{6}$

= 3.5 ∀ i = 1(1)10 and j = 1(1)20

and,

$E(X^{2}_{ij}$ = $\frac {1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + 6^{2}}{6}$

= $\frac {1 + 4 + 9 + 16 + 25 + 36}{6}$

= $\frac {91}{6}$

$\simeq$ 15.166667

so, $Var(X_{ij}$ = $(E(X^{2}_{ij} - {(E(X_{ij})}^{2})$

$\simeq 15.166667 - 3.5^{2}$

= 2.91667

and $\sigma_{X_{ij}}$ = $\sqrt {2.91667}[/tex [tex]\simeq 1.7078261036$

Now we get that,

$Y_{j} = \frac {\sum_{j = 1}^{20}X_{ij}}{20}$

We get that $Y_{j}'s$ are iid RV's ∀ j = 1(1)20

Let, ${\overline}{Y} = \frac {\sum_{j = 1}^{20}Y_{j}}{20}$

So, we get that $E({\overline}{Y}) = E(Y_{j})$

= $E(X_{ij}$ for any i = 1(1)10

= 3.5

and,

$\sigma_{({\overline}{Y})} = \frac {\sigma_{Y_{j}}}{\sqrt {20}} = \frac {\sigma_{X_{ij}}}{\sqrt {20}} = \frac {1.7078261036}{\sqrt {20}} [tex]\simeq 0.38$

Hence, the option which best describes the distribution being simulated is given by,

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

6 0

3 years ago

Write money amounts using a leading zero if necessary & with 2 decimal places (For example: 0.80 or 0.72 or 1.23)

goldenfox [79]

9514 1404 393

Answer:

63 mph
3 donut holes per kid
$0.70 per pound
$2.25 per km

Step-by-step explanation:

In this context, "per" and "for" mean "divided by."

630 mi/(10 h) = 63 mi/h
(24 dh)/(8 kid) = 3 dh/kid
$3.50/(5 lb) = $0.70 /lb
$32/(14 2/9 km) = $32/(128/9 km) = $(9/4)/km = $2.25 /km

3 0

3 years ago

Solve for y<br> 4.2x - 1.4y = 2.1

Harlamova29_29 [7]

4.2x - 1.4y = 2.1 |multiply both sides by 10

42x - 14y = 21 |subtract 42x from both sides

-14y = 21 - 42x |change signs

14y = 42x - 21 |divide both sides by 14

y = 3x - 1.5

8 0

3 years ago

A toy previously sold for $10.00 now sells for 75 cents. Calculate the decrease in the value of the toy

kramer

The decrease in the value of the toy is $9.25 if you subtract $ 0.75 from $10.00 then you get $9.25 so it's $9.25 cheaper

7 0

3 years ago

The total pay for 12 hours of work at a base rate of (p) per hour plus a temporary raise of $2.50 per hour. How would I write th

Naddika [18.5K]

12P+2.50 HOPE THIS HELPS

4 0

3 years ago